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What is the energy difference between the two lowest energy levels for a proton in a cubical box with side length1.00x10-14m, the approximate diameter of a nucleus?

Short Answer

Expert verified

The energy difference between the two lowest energy levels for a proton is∆E=9.89×10-13J=6.162MeV

Step by step solution

01

Energy Formula

In a cubical box with side length L, the allowed energies for a particle of mass m are given by;

Enx,ny,nz=(nX2+nY2+nZ2)Ï€2h22mL2

02

The energy difference between the two lowest energy levels for a proton

nX,nY,nZ=1,1,1corresponds to the lowest level, so

nX2+nY2+nz2)L=12+(]2+(1)2=3

and one of the combinations nX,nY,nz=2,1,1, nX,nY,nz=1,2,1, and nX,nY,nZ=1,1,2corresponds to the second-lowest energy;

nx2,ny2,nz2L=22+12+12=6

The energy separation between these two levels can be calculated using the equation:

∆E=Eu-EL=6π2h2meL-3π2h22meL2∆E=3π2h22meL2

Putting the values together now;

∆E=3π21.055×10-34J.s221.67×10-27kg1.0×10-14m2=9.89×10-13∆E=9.89×10-13J=6.162MeV

Hence, the energy difference between the two lowest energy levels for a proton is∆E=9.89×10-13J=6.162MeV

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