Chapter 6: Q6DQ (page 1519)
Why can’t an electron decay to two photons? To two neutrinos?
Short Answer
The electron cannot decay to two photons or two neutrinos as this would violate the conservation of charge.
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Chapter 6: Q6DQ (page 1519)
Why can’t an electron decay to two photons? To two neutrinos?
The electron cannot decay to two photons or two neutrinos as this would violate the conservation of charge.
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The wave functions for a particle in a box (see Fig. 40.12a) are zero at certain points. Does this mean that the particle can’t move past one of these points? Explain.
Analysis of the photon absorption spectrum of a diatomic molecule shows that the vibrational energy levels for small values of n are very nearly equally spaced but the levels for large n are not equally spaced. Discuss the reason for this observation. Do you expect the adjacent levels to move closer together or farther apart as n increases? Explain.
A particle is confined to a finite potential well in the region 0 < x < L . How does the area under the graph of in the region 0 < x < L compare to the total area under the graph of when including all possible x?
Figure 40.15a shows that the higher the energy of a bound state for a finite potential well, the more the wave function extends outside the well (into the intervals and ). Explain why this happens.
The electrical conductivities of most metals decrease gradually with increasing temperature, but the intrinsic conductivity of semiconductors always increases rapidly with increasing temperature. What causes the difference?
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