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Chapter 6: Q58P (page 1251)

Two events are observed in a frame of reference S to occur at the same space point, the second occurring 1.80s after the first. In a frame S鈥� moving relative to S, the second event is observed to occur 2.15s after the first. What is the difference between the positions of the two events as measured in S鈥�?

Short Answer

Expert verified

The difference between the positions of the two events as measured in S is3.53脳108m/s .

Step by step solution

01

Definition of Velocity

The term velocity may be defined as the ratio of displacement and time.

02

Determine the difference between the positions of the two events as measured in S’

The relation of time interval of two events in S and S'

鈭�t=鈭�t1-u2/c2

Solve for

Than

u=c1-鈭�t鈭�t2u=c1-1.80s2.15s2u=0.547c

Now the coordinates of first and second event related with each other as

鈭�x=-u鈭�t

So

鈭�x=0.547c鈭�t鈭�x=0.547c3.00脳108m/s鈭�x=3.53脳108m/s

Hence, the difference between the positions of the two events as measured in S is3.53脳108m/s .

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