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Radiation Therapy with π-Mesons. Beams ofπ-mesons are used in radiation therapy for certain cancers. The energy comes from the complete decay of the π-to stable particles.(a) Write out the complete decay of aπ-meson to stable particles. What are these particles?(b) How much energy is released from the complete decay of a single π-meson to stable particles? (You can ignore the very small masses of the neutrinos.)(c) How many π-mesons need to decay to give a dose of 50.0Gyto 10.0gof tissue?(d) What would be the equivalent dose in part (c) in Svand in rem? Consult Table 43.3 and use the largest appropriate RBE for the particles involved in this decay.

Short Answer

Expert verified
  1. The complete decay of a π-meson to a stable particle is π→e+ν¯μ+νμ+ν¯e, and the particles are:

e--stable electron

μ-- Muon

ν¯μ- Muon neutrino

ν¯e-Muon electron neutrino

b. The energy released from the complete decay of a singleπ-meson to the stable particle is 139.5MeV.

c. 2.24×1010particles π-meson needs to decay a dose of 50Gyto 10gof tissue.

d. The equivalent dose is75.0Svor 7500rem.

Step by step solution

01

Define the Absorbed dose and Equivalent dose

The ratio of total energy delivered to the mass of the tissue is known as the absorbed dose.

Absorbed dose=Total energy deliveredMass of the tissue

=Em

The unit of absorbed dose is Gray Gy and 1Gy=1.0J/kg.

The product of the absorbed dose and the RRB of the radiation is known as the biological equivalent dose.

Equivalent doseSv=PBE×Ansprbed doseGy

Also, 1.0rem=100Sv.

02

Determine the complete decay and energy released

a)

The complete decay of π-meson to the particle is:

π→μ-+ν¯μπ-→e+ν¯μ+νμ+ν¯e∵μ-=e+νμ+ν¯e

Where, the particles are:e-- stable electron Muon, ν¯μ-Muon neutrino and ν¯e-Muon electron antineutrino.

b)

The rest energy Erπ-of π-is 140MeV, and the rest energyEre-of the electron is 0.511MeV.

Assume that, the decay ends up with the electron, and decay starts withπ-particles when it is at rest.

So,

Q=Erπ--Ere-

Substituting the values, and we get,

Q=140-0.511=139.5MeV

Hence, the energy released from the complete decay of a single π- meson to the stable particle is 139.5MeV.

03

Determine the number of particles and equivalent dose.

c)

Given that,

Asorbed dose=50.0Gym=0.10g

The number of π-mesons required;

N=EQ=absorbed dose×mQ=500.010139.51.60×10-13=2.24×1010particle

Hence, 2.24×1010particle π-meson needs to decay a dose of 50Gyto 10gof tissue.

d)

The largest value of RBE for the electron is 1.50Sv/Gy.

The equivalent dose in Sv:

Equivalent dose=1.50×50=75.0Sv

Now, since 1.0rem=100Sv

Therefore, Equivalent dose=7500rem.

Hence, the equivalent dose is 75.0Sv or 7500rem.

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