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If a muon is traveling at 0.999c, what are its momentum and kinetic energy? (The mass of such a muon at rest in the laboratory is 207 times the electron mass.)

Short Answer

Expert verified

The momentumP=1.27*10-18kg/s and kinetic energy K=3.63*10-10J

Step by step solution

01

Step 1:Formula of relativistic momentum and kinetic energy(K).

K=mc21-v2/c2-γmv

Where,

P→momentumγ→lorentzfactorm→restmassv→velocity

Kinetic energy is,

width="179" height="74" role="math">P=mv2-v2/c2=γmvK=(γ-1)mc2

02

Step 2:Calculating the momentum.

Given a muon is travelling at 0.999c

The mass of muon is207me=1.89*10-28kg

Therefore the momentum is,

role="math" localid="1664101880227" P=mv1-v2/c2=(1.89*10-28kg)(0.999*3*108m/s)1-(0.999c)2/c2=1.27*10-18

03

Step 3:Calculating the kinetic energy.

The kinetic energy is,

P=mv1-v2/c2-mc2=(1.89*10-28kg)(3*108m/s)21-(0.999c)2/c2-(1.89*1028kg)(3*108m/s)2=3.63*10-10J

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