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Question: The human eye is most sensitive to green light of wavelength 505 nm. Experiments have found that when people are kept in a dark room until their eyes adapt to the darkness, a singlephoton of green light will trigger receptor cells in the rods of the retina. (a) What is the frequency of this photon? (b) How much energy (in joules and electron volts) does it deliver to the receptor cells? (c) To appreciate what a small amount of energy this is, calculate how fast a typical bacterium of mass 9.5 x 10-12 g would move if it had that much energy.

Short Answer

Expert verified

The photon鈥檚 frequency, energy and velocity are 5.941014Hz,2.46eV,9.1mm/srespectively.

Step by step solution

01

(a) Determination of the frequency of the photon.

The frequency of a photon is,

f=c

Substitute c=3108m/sand=50510-9m

f=3108m/s50510-9m=5.941014m

02

(b) Determination of energy delivered to receptor cells.

The energy of a photon is,

E = hf

Substituteh=6.62610-34Jsandf=5.941014Hz

E=6.62610-34Js5.941014Hz=3.0410-19J=2.46eV

03

(b) Determination of the velocity of the bacterium. 

The kinetic energy of the photon is,

K=12mv2

Solve for the velocity,

v=2Km

Substitute all the values in above equation,

v=23.9410-19J9.510-15kg=9.1mm/s

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