91影视

his height from small hole diameter.

$\sqrt{2gh}$is efflux speed from small hole.

Bernoulli's principle states that as the velocity of a liquid rises, the pressure falls, and when the speed lowers, the pressure increases.

We have to apply Bernoulli鈥檚 equation to fluid in the siphon.

As long as the water is still moving upward before exiting the syphon, it makes no difference to how fast it leaves.

The efflux speed is given as,

If the absolute (not gauge) pressure is negative, water will not flow. Even if the gauge pressure is negative, water will not flow. The bottom of the hose is exposed to the environment.

Pressure at the top of siphon is given as,

$p=p_a-蚁g\left(H+h\right)$

Here, cross-sectional is constant and is constant.

Putting, p = 0 in equation,

$H=\left(\frac{p_a}{蚁g}\right)-h$

But theresult shows $\left(H+h<\frac{p_a}{蚁g}\right)$. For water and normal atmospheric pressure, the value of $\frac{p_a}{蚁g}$ is 10.3 m .