91影视

Given that three identical pucks on a horizontal air table have repelling magnets. They are held together and then released simultaneously. Each has the same speed at any instant. One puck moves due west.

Let west be positive x axis and north be positive y-axis.

Let object A moves west.

Let speed of each puck is v.

Applying conservation of momentum along x-axis

$0=-mv+m{v}_{Bx}+m{v}_{Cx}$

This implies $v=v_{Bx}+v_{Cx}$

Applying conservation of momentum along y-axis

$0=m{v}_{By}+m{v}_{Cy}$

This implies $v_{By}=-v_{Cy}$

Since$v_B=v_C$ and y component has equal magnitude, so x-component must also have equal magnitude.

So $v_{Bx}=v_{Cx}$

Thus$v=v_{Bx}+v_{Cx}$ implies $v_{Bx}=v_{Cx}=\frac{v}{2}$

The angle$胃$ that puck B makes with x-axis is given by $\cos 胃=\frac{v/2}{v}=\frac{1}{2}$

Thus $胃=60掳$.

Hence, one puck moves in a direction$60掳$ north of east and other puck moves in a direction $60掳$south of east.