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The deepest point known in any of the earth’s oceans is in the Marianas Trench, 10.92 km deep. (a) Assuming water is incompressible, what is the pressure at this depth? Use the density of seawater. (b) The actual pressure is1.16×108Pa ; your calculated value will be less because the density actually varies with depth. Using the compressibility of water and the actual pressure, find the density of the water at the bottom of the Marianas Trench. What is the percent change in the density of the water?

Short Answer

Expert verified

(a)1.10×108Pa

(b)1.08×103kg/m3

Step by step solution

01

Given information:

p=1.16×108Pa,h=10.92×103m

02

Concept/Formula used:

The variation in pressure due to depth is given by

P=P0+ÒÏgh

Where,

ÒÏIs density of fluid and

h Is depth

03

Pressure calculation in depth

(a)

Density of seawaterÒÏ=1.03×103kg/m3

p0=pair+ÒÏgh=1.01×105Pa+1.03×103kg/m39.80m/s210.92×103m=1.10×108Pa
04

Density of water at bottom

(b)

ΔV=−(Δp)V0β=−1.10×108Pa1.00m32.2×109Pa=−−0.050m3∵V=V0+ΔV=1−0.05=0.950m3ÒÏ=mV=1.03×103Kg0.950m3=1.08×103kg/m3

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