91影视

The given data can be listed below as,

• The mass of stone is, $m=0.80\text{鈥塳驳}$.
• The length of the string is,$r=0.90\text{鈥尘}$ .
• The tensile strength of the string is,$T=60.0\text{鈥塏}$ .

Tension is a force which is carried by a flexible medium such as rope, string, and cable, etc. Tension force acts along the length of the rope, string, cable, etc.

Part (a)

The free body diagrams of the stone can be expressed as,

Part (b)

The relation of tension with centripetal force can be expressed as,

$T=\frac{m{v}^2}{r}$

Here $m$is the mass of the stone, $r$is the length of the string, $v$is the maximum speed of the stone.

Substitute 0.80 kg for$m$, 0.90 m for$r$ , 60.0 N for $T$in the above equation,

$\begin{array}{c}60.0\text{鈥塏}=\frac{0.80\text{鈥塳驳}脳v^2}{0.90\text{鈥尘}}\\ v=\sqrt{\frac{0.90\text{鈥尘}脳60.0\text{鈥塏}}{0.80\text{鈥塳驳}}}\\ =8.21\text{鈥尘/蝉}\end{array}$

Hence, the required maximum speed is,$8.21\text{鈥尘/蝉}$ .