/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q49E Viscous blood is flowing through... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 1: Q49E (page 393)

Viscous blood is flowing through an artery partially clogged by cholesterol. A surgeon wants to remove enough of the cholesterol to double the flow rate of blood through this artery. If the original diameter of the artery is D, what should be the new diameter (in terms of D) to accomplish this for the same pressure gradient?

Short Answer

Expert verified

The new diameter is 1.189 D .

Step by step solution

01

Given data

The original diameter is D.

02

Concept of the Poiseuille’s equation

In this problem, Poiseuille鈥檚 equation will be used to evaluate the new diameter in order to accomplish the double-flow rate of blood through the artery.

03

Determination of the flow rate of the blood

The relation of volume flow rate can be written as:

V=P蟺r48畏L

Here, P is the pressure difference, r is the radius, n is the dynamic viscosity and L is the length of the pipe.

The relation of new flow rate can be written as:

Vn=2VP蟺rn48畏L=2P蟺r48畏Lrn4=2r4

04

Determination of the new diameter of the artery

Substitute D2for r and Dn2for rnin the above relation.

Dn24=2D24Dn4=2(D)4Dn=(2)1/4(D)

On further solving the above relation.

Dn=1.189D

Thus, the new diameter is 1.189 D .

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A Simple Reaction-Time Test.A meter stick is held vertically above your hand, with the lower end between your thumb and first finger. When you see the meter stick released, you grab it with those two fingers. You can calculate your reaction time from the distance the meter stick falls, read directly from the point where your fingers grabbed it. (a) Derive a relationship for your reaction time in terms of this measured distance, d. (b) If the measured distance is 17.6 cm, what is your reaction time?

An antelope moving with constant acceleration covers the distance between two points 70.0apart in6.00s. Its speed as it passes the second point is15.0m/s. What are (a) its speed at the first point and (b) its acceleration?

On a training flight, a student pilot flies from Lincoln, Nebraska, to Clarinda, Iowa, next to St. Joseph, Missouri, and then to Manhattan, Kansas

(Fig. P1.66). The directions are shown relative to north: 0掳is north, 90掳is east, 180掳is south, and 270掳is west. Use the method of components to find (a) the distance she has to fly from Manhattan to get back to Lincoln, and (b) the direction (relative to north) she must fly to get there. Illustrate your solutions with a vector diagram.

A car and a truck start from rest at the same instant, with the car initially at some distance behind the truck. The truck has a constant acceleration of20m/s2, and the car has an acceleration of3.40m/s2. The car overtakes the truck after the truck has moved60.0m. (a) How much time does it take the car to overtake the truck? (b) How far was the car behind the truck initially? (c) What is the speed of each when they are abreast? (d) On a single graph, sketch the position of each vehicle as a function of time. Takex=0at the initial location of the truck.

Mass Mis distributed uniformly over a disk of radius a. Find the

gravitational force (magnitude and direction) between this disk-shaped mass

and a particle with mass mlocated a distance xabove the centre of the disk

(Fig. P13.81). Does your result reduce to the correct expression as xbecomes

very large? (Hint:Divide the disk into infinitesimally thin concentric rings, use

the expression derived in Exercise 13.35 for the gravitational force due to each

ring, and integrate to find the total force.)
See all solutions

Recommended explanations on Physics Textbooks

Dynamics

Read Explanation

Oscillations

Read Explanation

Rotational Dynamics

Read Explanation

Magnetism and Electromagnetic Induction

Read Explanation

Physical Quantities And Units

Read Explanation

Turning Points in Physics

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.