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A force in the +x direction with magnitude F(x)=18.0N-(0.530N/m)xis applied to a 6.00kgbox that is sitting on the horizontal, frictionless surface of a frozen lake. F(x)is the only horizontal force on the box. If the box is initially at rest at x=0, what is its speed after it has traveled 14.0m ?

Short Answer

Expert verified

8.17m/s

Step by step solution

01

Identification of given data

Mass of block ism=6.00kg

Distance travelled by block is14.0m

02

Significance of law of conservation of energy

Energy cannot be created or destroyed; it can only be transformed from one form into another or transferred from one object to another, according to the physical rule of conservation of energy.

03

Determining the speed

Firstly determine the work done and it is given as

W=x=0x=14Fxdx

Substitute all the value in above equation to get the value of work done

W=x=0x=1418.0N-(0.530N/m)xdx=18.0Nx-(0.530N/m)x22x=0x=14=200.06J

This work done will be equal to the change in kinetic energy by the law of energy conservation, so

W=12mv2-12mu2 ...(i)

Where uis initial velocity and is the final velocity

It is given in the question that the initial velocity is zero so the initial velocityu=0

Substitute all the values in equation (i)

200.06J=126kgv2v=8.17m/s

Hence the speed is8.17m/s

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