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Chapter 1: Q37E (page 331)

Find the magnitude of the angular momentum of the second hand on a clock about an axis through the center of the clock face. The clock hand has a length of 15.0cmand a mass of 6.00g. Take the second hand to be a slender rod rotating with constant angular velocity about one end.

Short Answer

Expert verified

Hence, the angular momentum is 4.71脳10-6kgm2/s.

Step by step solution

01

Definition of angular momentum of second hand of a clock

The magnitude of angular momentum of second hand of a clock about an axis through the center of the clock face (a symmetry axis) is found using,

L=I蝇

Where, Iis moment of inertia of rod rotating about an axis through one end ie, I=13ml2

Then, the angular momentum is written as:

L=13ml2蝇

02

Evaluate the angular momentum

Since, second hand makes a complete revolution each 60seconds, its angular speed is:

蝇=1rev60s=2蟺rad60s

The angular momentum is calculated as follows:

L=13ml2蝇=13ml22蟺rad60s=13脳6脳10-3脳0.15022蟺rad60s=4.71脳10-6kgm2/s

Thus, the angular momentum is 4.71脳10-6kgm2/s.

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