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Chapter 1: Q34E (page 392)

A solid aluminium ingot weighs 89 N in air. (a) What is its volume? (b) The ingot is suspended from a rope and totally immersed in water. What is the tension in the rope (the apparent weight of the ingot in water)?

Short Answer

Expert verified

Volume of aluminium ingot(V)=3.4脳10-3m3

Buoyant forceFb=33.32N

Tension of ropeTr=55.7N

Step by step solution

01

Identification of given problem

Weight of aluminium ingotwal=89N

02

Significance of Archimedes’ principle

The buoyant force is the upward attraction of a fluid on a body. Archimedes' principle asserts that a buoyant force equals the object's weight in fluids.

03

Determination of buoyant force

To find volume of ingot:

V=m蚁W=mgm=WgV=W蚁g

Putting values in equation,

V=892.7脳10鈭�3(9.81)=3.4脳10鈭�3TofindbuoyantforceFbuoyant=蚁wVg鈦�(1000)3.4脳10鈭�3(9.8)=33.32N

04

Step 4:Determination of total upward force

Total upward force=Fbuyo+Ttension=Fbuyo+Ttension=WT=W鈭�Fbuyo=(89鈭�33.3)N=55.7N

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