91Ó°ÊÓ

The given data can be listed below,

• The length of the aorta is,$l=16cm$ .
• The force exerted on the aorta is,$F=1.50N$ .
• The stretch in the aorta is,$x=3.75cm$ .

When describing a physical motion or movement, the term "force" alludes to strength or energy. It is physical motion or movement that demonstrates strength or vigour.

The force constant of the aorta is given by,

$$\begin{gathered} F=kx \\ k=\frac{F}{x} \end{gathered}$$

Here, F is the force on the aorta, and x is the stretch in the aorta.

Substitute all the values in the above,

$$\begin{gathered} k=\frac{1.50N}{0.0375m} \\ =40N/m \end{gathered}$$

Thus, the force constant of the aorta is 40 N/m .

The force on the aorta is given by,

F = kx

Here, k is the force constant, and x is the maximum distance of stretch.

Substitute all the values in the above,

$$\begin{gathered} F=\left(40N/m\right)\left(1.14m\right)\left(\frac{{10}^{-2}m}{1cm}\right) \\ =0.456N \end{gathered}$$

Thus, the force on the aorta when the stretch is 0.0114 m is 0.456 N .