91Ó°ÊÓ

The given data can be listed below.

Motion that follows a curved course is known as circular motion. Uniform circular motion is the description of a body traveling along a circular route with a constant (uniform) speed.

The linear velocity of the passenger is constant so the acceleration of the passenger is centripetal and in an upward direction which is given by,

$a=\frac{v^2}{R}$

Here, v is the linear velocity of the passenger, and R is the radius of the wheel.

Substitute all the values in the above,

$\begin{array}{rcl}a& =& \frac{{\left(6m/s\right)}^2}{14m}\\ & =& 2.57m/s^2\end{array}$

Thus, the magnitude of acceleration is $2.57m/s^2$and it is pointed in upward direction.

The centripetal acceleration is constantly pointed in the direction of the center and has the same magnitude at every point along a curved route.

Thus, the acceleration of the passenger is 2.57 m/s² downhill at the maximum point.

The time taken by the Ferris wheel for one revolution is given by,

$T=\frac{2\mathrm{Ï€¸é}}{v}$

Here, v is the linear velocity of the passenger, and R is the radius of the wheel.

Substitute all the values in the above,

$\begin{array}{rcl}T& =& \frac{2\left(3.14\right)\left(14m\right)}{6m/s}\\ & =& 14.66s\end{array}$

Thus, the time taken by the Ferris wheel to complete one revolution is 14.66 s.