/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q1DQ The sign of many physical quanti... [FREE SOLUTION] | 91影视

91影视

The sign of many physical quantities depends on the choice of coordinates. For example,ay for free-fall motion can be negative or positive, depending on whether we choose upward or downward as positive. Is the same true of work? In other words, can we make positive work negative by a different choice of coordinates? Explain.

Short Answer

Expert verified

The explanation is not true for work, and the work does not depend on the choice of axis orientations.

Step by step solution

01

Describe the Work-Energy theorem

The work energy theorem tells that the work done on the body results in a change in its kinetic energy.

Wtotal=K2-K1=K

02

Determine whether the explanation is also true for work also determine whether it is possible to make e positive work negative by a different choice of coordinates

It is known that the kinetic energy of a particle is only dependent on the instantaneous speed of the particle. The sign of the total work done on the particle cannot depend on the orientations of the coordinate axes. It is positive if the particle speeds up and negative if it stows down.

From the definition of work, this is known that if both the force and the displacement change their direction, the overall sign will remain the same.

Therefore, the given explanation is not true for work, and work exerted on the body does not depend on the choice of axis orientations.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

For a spherical planet with mass M, volume V, and radius R,derive an expression for the acceleration due to gravity at the planet鈥檚 surface, g, in terms of the average density of the planet, =M/V, and the planet鈥檚 diameter, D=2R. The table gives the values of Dand gfor the eight major planets:

(a) Treat the planets as spheres. Your equation for as a function of and shows that if the average density of the planets is constant, a graph of versus will be well represented by a straight line. Graph as a function of for the eight major planets. What does the graph tell you about the variation in average density? (b) Calculate the average density for each major planet. List the planets in order of decreasing density, and give the calculated average density of each. (c) The earth is not a uniform sphere and has greater density near its center. It is reasonable to assume this might be true for the other planets. Discuss the effect this nonuniformity has on your analysis. (d) If Saturn had the same average density as the earth, what would be the value of at Saturn鈥檚 surface?

You are on the roof of the physics building, 46.0mabove the ground (Fig. P2.70). Your physics professor, who is1.80mtall, is walking alongside the building at a constant speed of1.20m/s. If you wish to drop an egg on your professor鈥檚 head, where should the professor be when you release the egg? Assume that the egg is in free fall.

(Fig. P2.70)

A circular racetrack has a radius of 500 m. What is the displacement of a bicyclist when she travels around the track from the north side to the south side? When she makes one complete circle around the track? Explain.

Air traffic controllers give instructions called 鈥渧ectors鈥 to tell airline pilots in which direction they are to fly. If these are the only instructions given, is the name 鈥渧ector鈥 used correctly? Why or why not?

Question- Neptunium. In the fall of 2002, scientists at Los Alamos National Laboratory determined that the critical mass of neptunium-237 is about 60 kg. The critical mass of a fissionable material is the minimum amount that must be brought together to start a nuclear chain reaction. Neptunium-237 has a density of 19.5 g/cm3. What would be the radius of a sphere of this material that has a critical mass?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.