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An elaborate pulley consists of four identical balls at the ends of spokes extending out from a rotating drum (Fig. Q9.18). A box is connected to a light, thin rope wound around the rim of the drum. When it is released from rest, the box acquires a speed V after having fallen a distance d. Now the four balls are moved inward closer to the drum, and the box is again released from rest. After it has fallen a distance d, will its speed be equal to V, greater than V, or less than V? Show or explain why.

Short Answer

Expert verified

The velocity will be greater.

Step by step solution

01

Concept/Significance of rotational Moment of inertia

In order to find in which case the velocity would be greater or smaller, let’s discuss about the distribution of ,ass, because the four ball are moved inward closer to the drum.

The rotational moment of inertial is given by,

l=md2

02

Explain whether the speed be equal to V, greater than V, or less than V

It is known that the formula for rotational is l=md2and because the distance is reduced between the balls and the axis of rotation, rotational inertial of the system is going to reduced too. Therefore, l1>l2.

Draw the diagram for given situation.


Write the Newton’s equations for translational and rotational motion.

For case (1),

I1α1=τ1=T1R

For case (2),

I2α2=τ2=T2R

ExpressT1andT2from Newton’s equation for translational motion, and also note that m1=m2=m,

For case (1),

ma1=mg-T1T1=mg-ma1

For case (2),

ma2=mg-T2T2=mg-ma2

It is known thatα=αRthen,

For case (1),

l1a1R=mg-ma1R=mgR-ma1R

For case (2),

l2a2R=mg-ma2R=mgR-ma2R

Divide both sides with R.

l1a1R2=mg-ma1a1l1a1R2=mg

And,

l2a2R2=mg-ma2a2l2a2R2=mg

Final express the above equations for and .

a1=mgI1R2+m

And,

a2=mgI2R2+m

Because, l1>l2, the denominator in first case is going to be greater than denominator in second case. Depending on that, it will be that α1>α2.

Therefore, for some distance d, because the box in second case have greater linear acceleration, so ,it will have greater velocity too.

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