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Chapter 1: Q11E (page 59)

Neptunium. In the fall of 2002, scientists at Los Alamos National Laboratory determined that the critical mass of neptunium-237 is about 60kg. The critical mass of a fissionable material is the minimum amount that must be brought together to start a nuclear chain reaction. Neptunium-237 has a density of 19.5g/cm3. What would be the radius of a sphere of this material that has a critical mass?

Short Answer

Expert verified

Volume of 60kg material =3.076脳103cm3.

Radius of sphere of material =9.021cm.

Step by step solution

01

Given information

Neptunium mass =60Kg

Neptunium density =19.5g/cm3

02

Calculation of Volume of $60 \mathrm{~kg}$ material

The Volume is calculated as

V=m蚁

Herel

V is volume

M is mass

蚁= density

V=60Kg/19.5g/cm3103kg1gV=3.076脳103cm3
03

Calculating Radius of sphere of material

The Sphere radius is given as

V=43蟺R3R=3V4蟺3

Substituting the values as

R=3脳3/076脳103cm34蟺a

R=9.021cm

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