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Question: In another version of the 鈥淕iant Swing鈥 (see Exercise 5.50), the seat is connected to two cables, one of which is horizontal (Fig. E5.51). The seat swings in a horizontal circle at a rate of 28.0rpm. If the seat weighs 255N and an 825N person is sitting in it, find the tension in each cable.

Short Answer

Expert verified

Tension in the upper cables is1409.84N and tension of in the horizontal cables is6189.45N.

Step by step solution

01

Identification of given data

Weight of seatWc=255N

Weight of person Wp=255N

Seat swing at a rate of n=28.0rpm

Radius of circular pathr=7.5m.

02

Significance of centripetal force and centrifugal force

The force applied to an item in curved motion that is pointed toward the axis of rotation or the centre of curvature is known as a centripetal force.

A fictitious force that moves in a circle and is directed away from the centre of the circle is called centrifugal force.

Fc=mv2rormr2

Where, m is mass of body, v is velocity of body, r is radius of circular path and the is angular speed.

03

Determining the tension in each cable

Let assume that tension in upper cable is T1and the tension in the horizontal cable is T2

Total weight of seat and person is

W=255N+825N=1080N

Total mass of seat and person is

m=1080N9.8m/s2=110.204kg

Determine the angular speed of seat

=2n60=228.0rpm60=2.93rad/s

Equating the vertical forces

T1sin500=mg

Substituting all the values in above equation to get value oflocalid="1668424843713" T1

localid="1668424837705" T1=1080Nsin500=1409.84N

Hence the tension in the upper cables islocalid="1668424848310" 1409.84N

Now equating the horizontal forces

localid="1668424853079" Fc=T2+T1cos500mr2=T2+T1cos500

Substituting all the values in above equation to the value oflocalid="1668424865980" T2

localid="1668424858614" 110.204kg7.5m2.93rad/s2=T2+1409.84Ncos500T2=7095.67N-906.22N=6189.45N

Hence the tension in the horizontal cables is localid="1668424875875" 6189.45N.

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