91影视

The time constant is given as:$\mathit{蟿}\mathbf{=}\mathit{R}\mathit{C}$ , where R is the resistance of the resistor and C is the capacitance of the capacitor.

Loop rule for closed electric circuit:$\mathit{蔚}\mathbf{-}\mathit{l}\mathit{R}\mathbf{=}\mathbf{0}$ , where I is the current in the circuit, R is the resistance of the resistor, and$\mathit{蔚}$ is the electromotive force.

Consider a capacitor that is initially uncharged which is connected in series with a resistor and an emf source with $蔚=110V$and negligible internal resistance. Just after the circuit is completed the current through the resistor is $l=6.5脳{10}^{=5}A$. The time constant of the circuit is $蟿=5.2s$.

So, $RC=5.2s$ (1)

Just after the circuit is completed the capacitor acts like a wire, apply the loop rule:

$蔚-lR=0$

So,

$$\begin{gathered} R=\frac{蔚}{l}=\frac{110V}{6.5脳{10}^{-5}A}=1.7脳{10}^6惟 \\ R=1.7脳{10}^6惟 \end{gathered}$$

Use (1) to find C as

$$\begin{gathered} C=\frac{5.2s}{R}=\frac{5.2}{1.7脳{10}^6惟}=3.1渭F \\ C=3.1渭F \end{gathered}$$

Hence, the resistance and capacitance of the resistor and the capacitor are respectively $R=1.7脳{10}^6惟,C=3.1渭F$.