/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q72P A uniform bar has mass 0.0120 kg... [FREE SOLUTION] | 91影视

91影视

A uniform bar has mass 0.0120 kg and is 30.0 cm long. It pivots without friction about an axis perpendicular to the bar at point figure below. The gravitational force on the bar acts in the direction. The bar is in a uniform magnetic field that is directed into the page and has magnitude B = 0.150T . (a) What must be the current in the bar for the bar to be in rotational equilibrium when it is at an angle u=30above the horizontal? Use your result from Problem (A uniform bar of length carries a current in the direction from point to point . The bar is in a uniform magnetic field that is directed into the page. Consider the torque about an axis perpendicular to the bar at point that is due to the force that the magnetic field exerts on the bar. (a) Suppose that an infinitesimal section of the bar has length and is dx located a distance x from point . Calculate the torque about point due to the magnetic force on this infinitesimal section. (b) Use=abdtto calculate the total torque on the bar. (c) Show that is the same as though all of the magnetic force acted at the midpoint of the bar.) (b) For the bar to be in rotational equilibrium, should l be in the direction from a to b or b to a ?

Short Answer

Expert verified

The current I in the bar for the bar to be in rotational equilibrium when it is at an angleu=30 above the horizontal is I = 2.26A and the direction from a to b .

Step by step solution

01

Definition of magnetic field

The term magnetic field may be defined as the area around the magnet behave like a magnet.

02

Determine the current and direction

The current can be calculated by the relation

I=mgcos()BLI=(0.0120kg)9.80m/s2cos30.0(0.150T)(0.300m)I=2.26A

Hence, The current I in the bar for the bar to be in rotational equilibrium when it is at an angle u=30above the horizontal is I = 2.26A.

And the direction from the diagram is from a to b.

Hence, the direction from a to b.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The freshness of fish can be measured by placing a fish between the plates of a capacitor and measuring the capacitance. How does this work? (Hint: As time passes, the fish dries out. See Table )

An emf source with E = 120 V, a resistor with R = 80.0 鈩, and a capacitor with C = 4.00 碌F are connected in series. As the capacitor charges, when the current in the resistor is 0.900 A, what is the magnitude of the charge on each plate of the capacitor?

Question: A conducting sphere is placed between two charged parallel plates such as those shown in Figure. Does the electric field inside the sphere depend on precisely where between the plates the sphere is placed? What about the electric potential inside the sphere? Do the answers to these questions depend on whether or not there is a net charge on the sphere? Explain your reasoning.

Question: A 1500-W electric heater is plugged into the outlet of a 120-V circuit that has a 20-A circuit breaker. You plug an electric hair dryer into the same outlet. The hair dryer has power settings of 600 W, 900 W, 1200 W, and 1500 W. You start with the hair dryer on the 600-W setting and increase the power setting until the circuit breaker trips. What power setting caused the breaker to trip?

A 12.4-碌F capacitor is connected through a 0.895-M鈩 resistor to a constant potential difference of 60.0 V. (a) Compute the charge on the capacitor at the following times after the connections are made: 0, 5.0 s, 10.0 s, 20.0 s, and 100.0 s. (b) Compute the charging currents at the same instants. (c) Graph the results of parts (a) and (b) for t between 0 and 20 s

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.