Explanations 
Textbooks 
Flashcards 
91影视 AI 
Notes 
Study Plans 
Study Sets 
Find a degree 
Magazine Chapter 4: Q60P (page 781)
Two spherical shells have a common center. The inner shell has radius= 5.00 cm and charge; the outer shell has radius = 15.0 cm and chargelocalid="1664267292506" . Both charges are spread uniformly over the shell surface. What is the electric potential due to the two shells at the following distances from their common center: (a) r = 2.50 cm; (b) r = 10.0 cm; (c) r = 20.0 cm? Take V = 0 at a large distance from the shells.
Short Answer
- V = 240kV
- V = -30kV
- V = -90kV
Step by step solution
Step 1:
Given data:
Potential inside the sphere (r<R) where (R) is the radius of the sphere and the potential is constant
And if (r) is the distance, then the potential is;
Step 2:
At r=2.50cm=0.025m,
The total potential is the sum of the potential of two spheres for the first sphere and for the second sphere is .
Therefore, the equation is:
Step 3:
At r=10.0cm=0.10m
The total potential is the sum of the potential of two spheres for the first sphere and for the second sphere is .
Therefore, the equation is:
Step 4:
At r=20.0cm=0.20m
The total potential is the sum of the potential of two spheres for the first sphere and for the second sphere is .
Therefore, the equation is:
Over 30 million students worldwide already upgrade their learning with 91影视!
