91Ó°ÊÓ

According to Ohm’s law, the current flowing through the conductor is directly proportional to the voltage across the two points.

$V=IR$

Where, Iis current in ampere $\left(A\right)$, R is resistance in ohms$\left(\mathrm{Î\copyright }\right)$ and V is the potential difference volt$\left(V\right)$ .

Also,$V=EL$

Where, $E$is the electric field across conductor and $L$is length of the conductor.

The ratio of V to I for a particular conductor is called its resistance R :

$R=\frac{V}{I}$or$\frac{\mathrm{ÒÏ}L}{A}$

Where,$\mathrm{ÒÏ}$ is resistivity role="math" localid="1664170807826" $\mathrm{Î\copyright }·\mathrm{m}$, $L$is length in m and A is area in $m^2$.

Given that, the length $L$of two wires is 2000 m, the current $I_A$at point is A, current $I_B$at point B is 1.65 A and the voltage V at both points is 9.0 V . Consider short circuit at point C , length between the points A and C is $L_{CA}$and distance between the point B and C is $L_{CB}$.

So,$L_{CB}=2000-L_{CA}$

And${\mathrm{ÒÏ}}_{CA}={\mathrm{ÒÏ}}_{CB}$

Substitute the values in equation

Hence, the distance between the short circuit from the point A is $732.5\mathrm{m}$.