91影视

The horizontal bar is, l = 60.0 cm .

The uniform magnetic field is, B = 1.50 T .

The resistor is, $\mathrm{R}=5.00\mathrm{惟}$.

The maximum terminal voltage of the battery is, V = 1775 V .

A magnetic field is a field that describes the magnetic influence on a space object.

(a)

By varying current, the battery voltage is adjusted.to measure mass m apply magnetic field which has same magnitude of gravitational force in opposite direction so the magnetic field points upwards.by right hand rule current in the circuit flows in counter clockwise direction.

Thus, for this current flow the positive terminal of battery is a.

(b)

Maximum mass that instrument measure for V = 175 V is,

Angle between magnetic field and length is .magnitude of force is,

$F=llB\sin 蠒$

And

$I=\frac{V}{R}$

So,

$\begin{array}{r}F=\frac{VIB\sin 鈦�蠒}{R}\\ F=\frac{VIB}{R}\end{array}$ (1)

Here I is the current, l is the wire length, R is the resistance and B is the magnetic field.

For gravitational force is expressed as,

F = mg 鈥�(2)

From the equation (1) and (2).

$\begin{array}{r}mg=\frac{VIB}{R}\\ m=\frac{VIB}{gR}\end{array}$

Here m is the mass and g is the gravitational acceleration.

Substitute all the value in the above equation.

$\begin{array}{r}\mathrm{m}=\frac{\left(175\mathrm{V}\right)(0.600\mathrm{m})(1.50\mathrm{T})}{(5.00\mathrm{惟})\left(9.80\mathrm{m}/{\mathrm{s}}^2\right)}\\ =3.214\mathrm{kg}\\ \mathrm{m}=3.21\mathrm{kg}\end{array}$

Thus, the greatest mass m that this instrument can measure is m = 3.21kg .