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Chapter 4: Q28E (page 1074)

A laser beam has diameter 1.20 mm. What is the amplitude of the electric field of the electromagnetic radiation in this beam if the beam exerts a force of 3.8脳10-9Non a totally reflecting surface?

Short Answer

Expert verified

The amplitude of the electric field of the electromagnetic radiation is1.95脳104V/m .

Step by step solution

01

Radiation pressure exerted by electromagnetic wave

Radiation pressure is mechanical pressure exerted upon any surface due to the exchange of momentum between the object and the electromagnetic field.

The Radiation pressure exerted by electromagnetic wave is given by

prad=2Ic

Where, pradis the radiation pressure, I is the intensity and C is the speed of light.

Intensity of electromagnetic wave

Intensity of electromagnetic wave in terms of electric field

I=12蔚0cE2max

Where, 蔚0is the permittivity of vacuum ,role="math" localid="1664425325176" Emaxis the maximum amplitude of electric field and C is the speed of light.

02

Calculation of amplitude of electric field in EM wave in vacuum

Using

I=12蔚0cEmax2

Emax=2I蔚0c

Put the values of constants in above equation

Emax=2(5.04脳105W/m2)8.85脳10-12C2N.m2(3脳108m/s)Emax=1.95脳104V/m

Thus, the amplitude of the electric field of the electromagnetic radiation is 1.95脳104V/m.

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