91影视

Given data:

$$\begin{gathered} R_{N鈭�H}=0.11脳{10}^{鈭�9}\mathrm{m} \\ {\mathrm{R}}_{\mathrm{N}鈭�\mathrm{O}}=0.28脳{10}^{鈭�9}\mathrm{m} \\ {\mathrm{R}}_{\mathrm{N}鈭�\mathrm{N}}=0.3脳{10}^{鈭�9}\mathrm{m} \\ {\mathrm{q}}_{\mathrm{N}}={\mathrm{q}}_{\mathrm{H}}={\mathrm{q}}_{\mathrm{O}}=\mathrm{e} \end{gathered}$$

Force exerting by O on H-N, let the left direction be positive and the right direction be negative.

Therefore, the force between oxygen and hydrogen.

$$\begin{gathered} F_{O鈭�H}=\frac{K{e}^2}{R_{O鈭�H}^2} \\ =\frac{K{e}^2}{{\left(R_{O鈭�N}鈭�R_{N鈭�H}\right)}^2} \\ =\frac{\left(9脳{10}^9\right){\left(1.6脳{10}^{鈭�19}\right)}^2}{{\left[(0.28鈭�0.11)脳{10}^{鈭�9}\right]}^2} \\ =7.97脳{10}^{鈭�9}\mathrm{N} \end{gathered}$$

Forces Between oxygen and nitrogen

$$\begin{gathered} F_{O鈭�N}=\frac{K{e}^2}{R_{O鈭�N}^2} \\ =\frac{\left(9脳{10}^9\right){\left(1.6脳{10}^{鈭�19}\right)}^2}{{\left[0.28脳{10}^{鈭�9}\right]}^2} \\ =鈭�2.9脳{10}^{鈭�9}\mathrm{N} \end{gathered}$$

Force exerting by H-N on N, let the left direction be positive and the right direction be negative.

Therefore, force between hydrogen and nitrogen is

$$\begin{gathered} F_{N鈭�H}=\frac{K{e}^2}{R_{N鈭�H}^2} \\ =\frac{K{e}^2}{{\left(R_{N鈭�N}鈭�R_{N鈭�H}\right)}^2} \\ =\frac{\left(9脳{10}^9\right){\left(1.6脳{10}^{鈭�19}\right)}^2}{{\left[(0.3鈭�0.11)脳{10}^{鈭�9}\right]}^2} \\ =6.38脳{10}^{鈭�9}\mathrm{N} \end{gathered}$$

Force between nitrogen and nitrogen is

$$\begin{gathered} F_{NN}=\frac{K{e}^2}{R_{N鈭�N}^2} \\ =\frac{\left(9脳{10}^9\right){\left(1.6脳{10}^{鈭�19}\right)}^2}{{\left[0.3脳{10}^{鈭�9}\right]}^2} \\ =鈭�2.56脳{10}^{鈭�9}N \end{gathered}$$

So, the total net force is

$$\begin{gathered} F_{net}=(7.97鈭�2.9+6.38鈭�2.56)脳{10}^{鈭�9} \\ =8.89脳{10}^{鈭�9}N \end{gathered}$$

And force is directed towards the left which is attractive.

Hence, the Net force by thymine exerting on adenine is role="math" localid="1668165900263" $8.89脳{10}^{-9}N$, and it is an attractive force.

The force between electron and proton in a hydrogen atom

$$\begin{gathered} F_H=\frac{K{e}^2}{r^2} \\ =\frac{9脳{10}^9脳{\left(1.6脳{10}^{鈭�19}\right)}^2}{{\left(0.529脳{10}^{鈭�19}\right)}^2} \\ =8.23脳{10}^{鈭�8}\mathrm{N} \end{gathered}$$

The ratio is

$$\begin{gathered} R=\frac{8.23脳{10}^{鈭�8}}{8.89脳{10}^{鈭�9}} \\ 鈮�9.3 \end{gathered}$$

Therefore, The force between electron and proton in the hydrogen atom is $8.23脳{10}^{-8}N$, and its ratio is 9.3.