/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q11DQ Example 29.6 discusses the exter... [FREE SOLUTION] | 91影视

91影视

Example 29.6 discusses the external force that must be applied to the slide wire to move it at a constant speed. If there were a break in the left-hand end of theU-shaped conductor, how much force would be needed to move the slide wire at constant speed? As in the example, you can ignore friction.

Short Answer

Expert verified

Only need the force that sets the bar in motion and after that, do not need any force.

Step by step solution

01

Important Concepts

The entire magnetic field that travels across a particular region is measured by magnetic flux.

Magnetic flux is given by

=B.A

Where,B is the magnetic field andA is the area vector.

Faraday鈥檚 law states that, the induced emf in a coil is equal to the negative of the rate of change of magnetic flux times the number of turns in the coil. It involves the interaction of charge with the magnetic field.

emf=-Nt

Here, is the induced emf, N is the number of turns in the coil, and is the magnetic flux.

02

Application

In Example 29.6, the applied force is to oppose the magnetic force on the bar due to the current flowing in the bar in the magnetic field. And the current is induced due to the change in the area of the loop resulting in the change in the magnetic flux, according to Faraday's law. But, if there is a break in the loop, there is no induced current since the loop is openR= .

Thus, there is also no magnetic force, because the bar, in this case, is just a bar with no current in a magnetic field. Therefore, you only need the force that sets the bar in motion, and after that, you do not need any force. Of course, this is because friction is ignored.

Hence, only need the force that sets the bar in motion and after that do not need any force.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

(See Discussion Question Q25.14.) Will a light bulb glow more brightly when it is connected to a battery as shown in Fig. Q25.16a, in which an ideal ammeter is placed in the circuit, or when it is connected as shown in Fig. 25.16b, in which an ideal voltmeter V is placed in the circuit? Explain your reasoning.

A typical small flashlight contains two batteries, each having an emf of1.5V, connected in series with a bulb having resistance17. (a) If the internal resistance of the batteries is negligible, what power is delivered to the bulb? (b) If the batteries last for1.5hwhat is the total energy delivered to the bulb? (c) The resistance of real batteries increases as they run down. If the initial internal resistance is negligible, what is the combined internal resistance of both batteries when the power to the bulb has decreased to half its initial value? (Assume that the resistance of the bulb is constant. Actually, it will change somewhat when the current through the filament changes, because this changes the temperature of the filament and hence the resistivity of the filament wire.)

In the circuit, in Fig. E26.47 the capacitors are initially uncharged, the battery has no internal resistance, and the ammeter is idealized. Find the ammeter reading (a) just after the switch S is closed and (b) after S has been closed for a very long time.

In the circuit shown in Fig. E26.49, C = 5.90 mF, 詯 = 28.0 V, and the emf has negligible resistance. Initially, the capacitor is uncharged and the switch S is in position 1. The switch is then moved to position 2 so that the capacitor begins to charge. (a) What will be the charge on the capacitor a long time after S is moved to position 2? (b) After S has been in position 2 for 3.00 ms, the charge on the capacitor is measured to be 110 mC What is the value of the resistance R? (c) How long after S is moved to position 2 will the charge on the capacitor be equal to 99.0% of the final value found in part (a)?

The circuit shown in Fig. E25.33 contains two batteries, each with an emf and an internal resistance, and two resistors. Find (a) the current in the circuit (magnitude and direction) and (b) the terminal voltage Vabof the 16.0-V battery.

Fig. E25.33

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.