/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q10DQ A loose, floppy loop of wire is ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A loose, floppy loop of wire is carrying current I. The loop of wire is placed on a horizontal table in a uniform magnetic field B S perpendicular to the plane of the table. This causes the loop of wire to expand into a circular shape while still lying on the table. In a diagram, show all possible orientations of the current I and magnetic field B S that could cause this to occur. Explain your reasoning.

Short Answer

Expert verified

The force must be radially outward, the force acting on a wire carrying current is given by F→=I→L×B→so using right hand rule the force is outward if the current is flowing clockwise and the magnetic field points in to the plane, or if current flows counter clockwise and the magnetic field points outside the plane.

Step by step solution

01

Direction of Magnetic Field

Let us consider a loose, floppy loop of wire is carrying current I, which placed in a uniform magnetic field B that perpendicular to the plane of loop. This will cause the loop of the wire to expand into a circular shape. In order for this to occur the force must be radially outward, the force acting on a wire carrying current is given by F→=I→L×B→so using right hand rule the force is outward if the current is flowing clockwise and the magnetic field points in to the plane, or if current flows counter clockwise and the magnetic field points outside the plane.

02

Figure and Conclusion

Hence, the force must be radially outward, the force acting on a wire carrying current is given by F→=IL×B→so using right hand rule the force is outward if the current is flowing clockwise and the magnetic field points in to the plane, or if current flows counter clockwise and the magnetic field points outside the plane.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The tightly wound toroidal solenoid is one of the few configurations for which it is easy to calculate self-inductance. What features of the toroidal solenoid give it this simplicity?

Copper has 8.5×1022free electrons per cubic meter. A 71.0-cm

length of 12-gauge copper wire that is 2.05 mm in diameter carries 4.85 A of

current. (a) How much time does it take for an electron to travel the length

of the wire? (b) Repeat part (a) for 6-gauge copper wire (diameter 4.12 mm)

of the same length that carries the same current. (c) Generally speaking,

how does changing the diameter of a wire that carries a given amount of

current affect the drift velocity of the electrons in the wire?

Suppose a resistor R lies alongeach edge of a cube (12 resistors in all)with connections at the corners. Find theequivalent resistance between two diagonally opposite corners of the cube (pointsa and b in Fig. P26.84).

An idealized voltmeter is connected across the terminals of a15.0-Vbattery, and arole="math" localid="1655719696009" 75.0-Ω appliance is also connected across its terminals. If the voltmeter reads11.9V (a) how much power is being dissipated by the appliance, and (b) what is the internal resistance of the battery?

Question: A conducting sphere is placed between two charged parallel plates such as those shown in Figure. Does the electric field inside the sphere depend on precisely where between the plates the sphere is placed? What about the electric potential inside the sphere? Do the answers to these questions depend on whether or not there is a net charge on the sphere? Explain your reasoning.

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.