Chapter 26: Problem 86
Assume that a typical open ion channel spanning an axon's membrane has a resistance of 1 \(\times\) 10\(^{11}\) \(\Omega\). We can model this ion channel, with its pore, as a 12-nm-long cylinder of radius 0.3 nm. What is the resistivity of the fluid in the pore? (a) 10 \(\Omega\) \(\cdot\) m; (b) 6 \(\Omega\) \(\cdot\) m; (c) 2 \(\Omega\) \(\cdot\) m; (d) 1 \(\Omega\) \(\cdot\) m.
Short Answer
Step by step solution
Understand the formula for resistance
Identify the given values
Calculate the cross-sectional area
Solve for resistivity \( \rho \)
Perform the calculation
Select the correct answer
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Ion Channel
Cylindrical Conductor
Resistance Formula
- Resistance \(R\) represents how difficult it is for electricity (or ion flow in biological contexts) to move through a material.
- Resistivity \(\rho\) is a material-specific property that quantifies how strongly a material opposes the flow of electric current.
- The length \(L\) affects resistance linearly, meaning the longer the path for ion flow, the higher the resistance.
- The area \(A\) inversely affects resistance, with larger areas reducing resistance.