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Calculate the volume of 1.00 mol of liquid water at 20\(^\circ\)C (at which its density is 998 kg/m\(^3\)), and compare that with the volume occupied by 1.00 mol of water at the critical point, which is 56 \(\times\) 10\({^-}{^6}\) m\(^3\). Water has a molar mass of 18.0 g/mol.

Short Answer

Expert verified
The volume at 20°C is 3.22 times larger than at the critical point.

Step by step solution

01

Calculate the Mass of 1.00 mol of Water

Use the molar mass of water to calculate the mass:\[\text{mass} = \text{moles} \times \text{molar mass} = 1.00 \text{ mol} \times 18.0 \text{ g/mol} = 18.0 \text{ g}\]Convert the mass from grams to kilograms since density is given in kg/m³.\[18.0 \text{ g} = 0.018 \text{ kg}\]
02

Calculate the Volume at 20°C

Use the density formula to find the volume:\[\text{Volume} = \frac{\text{mass}}{\text{density}}\]Substitute the known values:\[\text{Volume} = \frac{0.018 \text{ kg}}{998 \text{ kg/m}^3} = 1.804 \times 10^{-5} \text{ m}^3\]
03

Compare the Volumes

We have the volume at 20°C as \(1.804 \times 10^{-5}\) m³ and the volume at the critical point as \(56 \times 10^{-6}\) m³. To compare the two volumes, use:\[\text{Comparison Ratio} = \frac{1.804 \times 10^{-5}}{56 \times 10^{-6}} \approx 3.22\]This shows that the volume at 20°C is approximately 3.22 times larger than the critical point volume.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Density
Density is a property of matter that expresses the relationship between mass and volume. It is typically represented by the symbol \(\rho\) and is defined by the equation:
  • \( \rho = \frac{\text{mass}}{\text{volume}} \)
Density tells us how much mass is contained in a given volume. This can help determine how objects will interact in their environment, such as whether they will float or sink. For liquid water at 20°C, the density is given as 998 kg/m³. This means for every cubic meter of this water, there are 998 kilograms of mass packed inside.
When calculating volume using density, like in the original problem, you rearrange the formula to solve for volume:
  • \( \text{Volume} = \frac{\text{mass}}{\text{density}} \)
Understanding how density relates to volume and mass is crucial in fields such as chemistry, physics, and engineering. In this context, knowing the density of water allows you to calculate its volume from its mass, providing insights essential for various applications.
Molar Mass
Molar mass is a fundamental concept in chemistry, representing the mass of one mole of any given substance. For water, the molar mass is 18.0 g/mol. The idea of moles and molar mass allows chemists to count atoms and molecules by weighing them.
To understand this better, consider that one mole of any element or compound contains the same number of particles, known as Avogadro's number, which is approximately \(6.022 \times 10^{23}\) particles.
Given the molar mass of water, it's straightforward to calculate the mass of any amount of water. For example, the mass of 1 mole of water is calculated as follows:
  • \( \text{mass} = \text{moles} \times \text{molar mass} = 1 \times 18.0 \text{ g/mol} = 18.0 \text{ g} \)
Understanding molar mass is crucial because it connects the macroscopic world we see to the microscopic world of atoms and molecules. It is used widely in converting laboratory measurements into amounts useful for scientific equations and reactions.
Critical Point
The critical point is a unique condition where distinct liquid and gas phases of a substance coexist and can no longer be distinguished. At this point, known as the critical temperature and critical pressure, the properties of the liquid and gas become identical.
For water, the critical point denotes the temperature and pressure at which water can exist in a kind of hybrid state, neither purely liquid nor purely gas. This state has significant implications in physics and chemistry, particularly concerning the behavior of substances at high pressures and temperatures.
In the exercise, the volume of water at the critical point is given and compared to its volume at 20°C. It serves as a practical illustration of how properties such as volume drastically change at extreme conditions. Recognizing the critical point is vital in areas such as thermodynamics and fluid mechanics, shaping our understanding of phase transitions and states of matter.

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Most popular questions from this chapter

Helium gas is in a cylinder that has rigid walls. If the pressure of the gas is 2.00 atm, then the root-mean-square speed of the helium atoms is \(\upsilon {_r}{_m}{_s}\) = 176 m/s. By how much (in atmospheres) must the pressure be increased to increase the \(\upsilon {_r}{_m}{_s}\) of the He atoms by 100 m/s? Ignore any change in the volume of the cylinder.

(a) What is the total translational kinetic energy of the air in an empty room that has dimensions 8.00 m \(\times\) 12.00 m \(\times\) 4.00 m if the air is treated as an ideal gas at 1.00 atm? (b) What is the speed of a 2000-kg automobile if its kinetic energy equals the translational kinetic energy calculated in part (a)?

What is one reason the noble gases are \(preferable\) to air (which is mostly nitrogen and oxygen) as an insulating material? (a) Noble gases are monatomic, so no rotational modes contribute to their molar heat capacity; (b) noble gases are monatomic, so they have lower molecular masses than do nitrogen and oxygen; (c) molecular radii in noble gases are much larger than those of gases that consist of diatomic molecules; (d) because noble gases are monatomic, they have many more degrees of freedom than do diatomic molecules, and their molar heat capacity is reduced by the number of degrees of freedom.

A large tank of water has a hose connected to it (Fig. P18.59). The tank is sealed at the top and has compressed air between the water surface and the top. When the water height \(h\) has the value 3.50 m, the absolute pressure \(p\) of the compressed air is 4.20 \(\times\) 10\(^5\) Pa. Assume that the air above the water expands at constant temperature, and take the atmospheric pressure to be 1.00 \(\times\) 10\(^5\) Pa. (a) What is the speed with which water flows out of the hose when \(h\) = 3.50 m? (b) As water flows out of the tank, \(h\) decreases. Calculate the speed of flow for \(h\) = 3.00 m and for \(h\) = 2.00 m. (c) At what value of h does the flow stop?

Three moles of an ideal gas are in a rigid cubical box with sides of length 0.300 m. (a) What is the force that the gas exerts on each of the six sides of the box when the gas temperature is 20.0\(^\circ\)C? (b) What is the force when the temperature of the gas is increased to 100.0\(^\circ\)C?

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