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A 15.0 -kg fish swimming at 1.10 \(\mathrm{m} / \mathrm{s}\) suddenly gobbles up a 4.50 -kg fish that is initially stationary. Neglect any drag effects of the water. (a) Find the speed of the large fish just after it eats the small one. (b) How much mechanical energy was dissipated during this meal?

Short Answer

Expert verified
(a) 0.846 m/s; (b) 2.105 J dissipated.

Step by step solution

01

Understand the Given Information

We have two fish: a large fish with a mass of 15.0 kg moving at a speed of 1.10 m/s, and a small fish with a mass of 4.50 kg that is initially stationary.
02

Conservation of Momentum

The conservation of momentum states that the total momentum before the event is equal to the total momentum after the event. The initial momentum is the momentum of the large fish, since the smaller fish is stationary. Therefore, the total initial momentum is: \(p_{initial} = (15.0 \, \text{kg})(1.10 \, \text{m/s}) = 16.5 \, \text{kg} \, \text{m/s}\).
03

Set Up Equation for Momentum Conservation

After the large fish eats the small fish, they become one system with a combined mass of \(15.0 \, \text{kg} + 4.50 \, \text{kg} = 19.5 \, \text{kg}\). Let \(v\) be the final velocity of the combined fish. According to momentum conservation: \(p_{initial} = p_{final}\), or \(16.5 = 19.5v\).
04

Solve for the Final Speed

Solve for \(v\) in the equation \(16.5 = 19.5v\):\[ v = \frac{16.5}{19.5} \approx 0.846 \, \text{m/s} \]
05

Calculate Initial Mechanical Energy

The initial mechanical energy is only kinetic and is given by the moving large fish: \[ KE_{initial} = \frac{1}{2} (15.0 \, \text{kg})(1.10 \, \text{m/s})^2 \approx 9.075 \, \text{J} \]The small fish is stationary so it contributes no initial energy.
06

Calculate Final Mechanical Energy

The final mechanical energy is also kinetic, involving the combined masses moving at the new velocity:\[ KE_{final} = \frac{1}{2} (19.5 \, \text{kg})(0.846 \, \text{m/s})^2 \approx 6.97 \, \text{J} \]
07

Find the Mechanical Energy Dissipated

The mechanical energy dissipated is the difference between initial and final mechanical energies:\[ \Delta KE = KE_{initial} - KE_{final} = 9.075 \, \text{J} - 6.97 \, \text{J} = 2.105 \, \text{J} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Mechanical Energy Dissipation
When we talk about mechanical energy dissipation, we refer to the energy that is lost from the system during a process. This loss happens because not all energy converted from one form stays entirely mechanical - some converts to other forms, like heat or sound. In the case of our two fish, the larger fish had more kinetic energy before it engulfed the smaller, stationary one.
However, after this action, even though the total mass increased, the kinetic energy decreased. The initial kinetic energy, with only the big fish moving, was approximately 9.075 J (joules). After swallowing the smaller fish, their combined movement had a decreased kinetic energy of about 6.97 J.
This reduction in energy, around 2.105 J, was dissipated. Mechanical energy dissipation is crucial to understand because it shows how systems can lose their operational energy, even when mass and some velocity are conserved.
Kinetic Energy
Kinetic energy is the energy an object possesses due to its motion. It can be calculated using the formula: \( KE = \frac{1}{2}mv^2 \), where \( m \) is mass and \( v \) is velocity. In our scenario with the two fish, the large fish's initial kinetic energy came from its movement at 1.10 m/s.
::Calculation of Initial Kinetic Energy:: To find the initial kinetic energy, we apply the formula to only the large fish, since the smaller fish wasn't moving, contributing no initial kinetic energy:
\( KE_{\text{initial}} = \frac{1}{2} \times 15.0 \times (1.10)^2 \approx 9.075 \, \text{J} \)::Calculation of Final Kinetic Energy:: After the large fish consumed the little one, both moved at a reduced velocity of 0.846 m/s, causing a drop in kinetic energy:
\( KE_{\text{final}} = \frac{1}{2} \times 19.5 \times (0.846)^2 \approx 6.97 \, \text{J} \)
The change in kinetic energy highlights the impact of mass and velocity on this form of energy, as well as energy diversion into other forms during physical interactions.
Momentum Conservation
In physics, the conservation of momentum principle is a fundamental rule stating that within a closed system, without external forces, the total momentum remains constant. Momentum itself is given by the product of an object's mass and velocity. It can be expressed by the formula: \( p = mv \).
::Before the Interaction::In our fish exercise, before the larger fish consumes the smaller, the only momentum comes from the large fish moving at 1.10 m/s:
\( p_{\text{initial}} = 15.0 \times 1.10 = 16.5 \, \text{kg} \, \text{m/s} \)::After the Interaction:: Once the big fish eats the smaller one, their total mass becomes 19.5 kg. After the event, we apply the principle of momentum conservation by stating that the initial and final momentum are equal:
\( 16.5 = 19.5 \times v \). Solving this equation gives us the final velocity \( v \approx 0.846 \, \text{m/s} \).
Conserving momentum explains how velocity changes with mass variations, all while maintaining the quantity of motion originally present in the system. It remains a vital concept in collision and consumption events like these to understand how movement transfers and adjusts.

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