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Two ice skaters, Daniel (mass 65.0 \(\mathrm{kg} )\) and Rebecca (mass \(45.0 \mathrm{kg} ),\) are practicing. Daniel stops to tie his shoelace and, while at rest, is struck by Rebecca, who is moving at 13.0 \(\mathrm{m} / \mathrm{s}\) before she collides with him. After the collision, Rebecca has a velocity of magnitude 8.00 \(\mathrm{m} / \mathrm{s}\) at an angle of \(53.1^{\circ}\) from her initial direction. Both skaters move on the frictionless, horizontal surface of the rink. (a) What are the magnitude and direction of Daniel's velocity after the collision? (b) What is the change in total kinetic energy of the two skaters as a result of the collision?

Short Answer

Expert verified
(a) Daniel's velocity: 7.2 m/s at 38.4°; (b) Change in kinetic energy: -677.7 J.

Step by step solution

01

Use the Conservation of Momentum in the x-direction

Since momentum is conserved and Rebecca is initially moving along the x-direction, we consider the conservation of momentum along both x and y axes separately. The total initial momentum in the x-direction is given by \( p_{x,i} = m_\text{Rebecca} \times v_\text{Rebecca} \), where \( m_\text{Rebecca} = 45.0 \, \mathrm{kg} \) and \( v_\text{Rebecca} = 13.0 \, \mathrm{m/s} \). Thus, \( p_{x,i} = 45.0 \times 13.0 = 585.0 \, \mathrm{kg\cdot m/s} \). After the collision, the x-component of Rebecca's velocity \( v_{Rx}' = 8.0 \cos(53.1^{\circ}) \) m/s, contributing \( 45.0 \times 8.0 \cos(53.1^{\circ}) \) kg·m/s. Let Daniel's x-component of velocity after collision be \( v_{Dx}' \). The equation becomes: \[ 585.0 = 45.0 \times 8.0 \cos(53.1^{\circ}) + 65.0 \times v_{Dx}' \].
02

Solve for Daniel's velocity in the x-direction

Calculate the x-component of Rebecca's velocity after the collision: \( v_{Rx}' = 8.0 \cos(53.1^{\circ}) = 4.8 \, \mathrm{m/s} \). Substitute into the momentum equation: \[ 585.0 = 45.0 \times 4.8 + 65.0 \times v_{Dx}' \]. Simplifying gives: \[ 585.0 = 216.0 + 65.0 \times v_{Dx}' \].Solving for \( v_{Dx}' \) yields: \[ v_{Dx}' = \frac{369.0}{65.0} = 5.68 \, \mathrm{m/s} \].
03

Use the Conservation of Momentum in the y-direction

Consider the y-direction, where the initial momentum is zero since Rebecca's initial movement is only in the x-direction.After collision, Rebecca's y-component is calculated: \( v_{Ry}' = 8.0 \sin(53.1^{\circ}) = 6.4 \, \mathrm{m/s} \).Thus, \[ 0 = 45.0 \times 6.4 - 65.0 \times v_{Dy}' \], where \( v_{Dy}' \) is Daniel's velocity in the y-direction.Solve this equation: \[ 0 = 288.0 - 65.0 \times v_{Dy}' \].
04

Solve for Daniel's velocity in the y-direction

Solving \( 65.0 \times v_{Dy}' = 288.0 \), we find\[ v_{Dy}' = \frac{288.0}{65.0} = 4.43 \, \mathrm{m/s} \].
05

Find the magnitude and direction of Daniel's velocity

Construct Daniel's velocity vector using components obtained:\[ v_D' = \sqrt{{v_{Dx}'}^2 + {v_{Dy}'}^2} = \sqrt{5.68^2 + 4.43^2} = 7.2 \, \mathrm{m/s} \].Find the direction using \( \theta = \tan^{-1} \left(\frac{v_{Dy}'}{v_{Dx}'}\right) = \tan^{-1} \left(\frac{4.43}{5.68}\right) = 38.4^{\circ} \) from the x-axis.
06

Calculate initial and final kinetic energies

Initial kinetic energy (K.E.) of Rebecca is \( KE_i = \frac{1}{2} m_\text{Rebecca} v_\text{Rebecca}^2 = \frac{1}{2} \times 45.0 \times (13.0)^2 = 3802.5 \, \mathrm{J} \). Daniel was at rest, hence his initial kinetic energy is 0 J.Final kinetic energy of Rebecca: \( KE_{Rf}' = \frac{1}{2} \times 45.0 \times (8.0)^2 = 1440.0 \, \mathrm{J} \).Final kinetic energy of Daniel: \( KE_{Df}' = \frac{1}{2} \times 65.0 \times (7.2)^2 = 1684.8 \, \mathrm{J} \).
07

Find the change in total kinetic energy

The change in total kinetic energy is given by:\[ \Delta KE = (KE_{Rf}' + KE_{Df}') - KE_i = (1440.0 + 1684.8) - 3802.5 \].Calculate using the previous step's results:\[ \Delta KE = 3124.8 - 3802.5 = -677.7 \, \mathrm{J} \].This indicates the kinetic energy decreased by 677.7 J.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Kinetic Energy
Kinetic energy is the energy an object possesses due to its motion. In the case of a collision, kinetic energy plays a crucial role in understanding the changes occurring as masses interact. Before the collision, the total kinetic energy is mainly due to Rebecca's movement across the ice, as she is the only one in motion.
The formula for calculating kinetic energy (KE) is: \[ KE = \frac{1}{2} m v^2 \] where \( m \) represents mass and \( v \) is velocity. For Rebecca, this was initially 3802.5 J while Daniel was stationary, hence his kinetic energy was zero. After the collision, both skaters continue moving, but each imparts different kinetic energies based on their masses and velocities. Rebecca's kinetic energy decreases to 1440.0 J, whereas Daniel, now set in motion, accumulates 1684.8 J. Despite energy changes depicted in the above values, the overall kinetic energy decreased by 677.7 J. This energy loss is typical of inelastic collisions, where kinetic energy isn't conserved.
Collision Dynamics
Collision dynamics involves the study of motion and interaction when two or more bodies collide. In this exercise, Daniel and Rebecca's collision is idealized to a frictionless surface, simplifying the analysis of their post-collision paths. A key feature of collision dynamics is understanding how bodies behave during the collision.
There are two primary types of collisions: elastic and inelastic. An elastic collision retains the same total kinetic energy before and after impact, whereas an inelastic collision, like the one between Daniel and Rebecca, sees a decrease in total kinetic energy. This loss can be due to factors such as deformation or sound energy production during the collision. In Rebecca and Daniel's case, the decrease in kinetic energy confirms the collision is inelastic. Observing the change in velocity and direction of both skaters post-collision helps us understand how momentum and energy translate through the collision dynamics.
Momentum in Physics
Momentum is a fundamental concept in physics involving the quantity of motion an object has, given by the product of its mass and velocity: \[ p = m imes v \]. It is a vector, meaning it has both magnitude and direction. In this scenario, the conservation of momentum principle applies, which states that the total momentum of a closed system remains constant if no external forces act on it. Before the collision, all momentum is with Rebecca moving at 13 m/s. Her total momentum is calculated as 585 kg·m/s. Afterwards, we must account for each skater's post-collision velocity to ensure total momentum remains unchanged.
By separately analyzing the x and y directional components (due to Rebecca's post-collision direction change), we determine both Daniel's and Rebecca's momenta adhere to conservation laws. Daniel reacts by moving with newly acquired momentum of 5.68 m/s along the x-axis and 4.43 m/s along the y-axis, demonstrating momentum's critical role in understanding these collision effects.

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