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A 10.0 -kg box is pulled by a horizontal wire in a circle on a rough horizontal surface for which the coefficient of kinetic friction is \(0.250 .\) Calculate the work done by friction during one complete circular trip if the radius is (a) 2.00 \(\mathrm{m}\) and (b) 4.00 \(\mathrm{m}\) . (c) On the basis of the results you just obtained, would you say that friction is a conservative or nonconservative force? Explain.

Short Answer

Expert verified
(a) The work done by friction is approximately 307.9 J. (b) For a 4.00 m radius, it's about 615.8 J. (c) Friction is a nonconservative force because it depends on the path.

Step by step solution

01

Understanding Work Done by Friction

When a box moves in a circle, the work done by friction is given by the formula: \( W = f_k \cdot d \), where \( f_k \) is the kinetic friction force and \( d \) is the distance traveled. For a complete circle, \( d = 2\pi r \).
02

Calculate Kinetic Friction Force

The kinetic friction force \( f_k \) is calculated using \( f_k = \mu_k \cdot F_n \), where \( \mu_k = 0.250 \) and \( F_n = mg \) for a horizontal surface. Therefore, \( f_k = \mu_k \cdot mg = 0.250 \cdot 10.0 \, \text{kg} \cdot 9.8 \, \text{m/s}^2 = 24.5 \, \text{N} \).
03

Calculate Work for Radius 2.00 m

Using \( d = 2\pi \cdot 2.00 \, \text{m} = 4\pi \, \text{m} \), we find the work done by friction: \( W = f_k \cdot d = 24.5 \, \text{N} \cdot 4\pi \, \text{m} = 98\pi \, \text{J} \approx 307.9 \, \text{J} \).
04

Calculate Work for Radius 4.00 m

Using \( d = 2\pi \cdot 4.00 \, \text{m} = 8\pi \, \text{m} \), the work done by friction: \( W = f_k \cdot d = 24.5 \, \text{N} \cdot 8\pi \, \text{m} = 196\pi \, \text{J} \approx 615.8 \, \text{J} \).
05

Evaluate Nature of Friction

Friction dissipates energy in the form of heat, regardless of path taken. Since the work done by friction depends on the path (circle size, in this case), it is a nonconservative force.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Kinetic Friction
Kinetic friction is the force that opposes the motion of two surfaces sliding past each other. In our exercise, the box moves across a rough surface. This friction is always present when there's motion, unlike static friction that occurs when objects are at rest. The formula to find the kinetic friction force (\( f_k \)) is given by:
  • \[ f_k = \mu_k \cdot F_n \]
Here, \( \mu_k \) is the coefficient of kinetic friction, and \( F_n \) is the normal force, which equals the gravitational force \( mg \) on a horizontal surface. Kinetic friction is crucial because it helps solve real-world problems where motion occurs, like in our box problem. It impacts how much energy is used to keep or stop motion, revealing much about energy efficiency in systems.
Nonconservative Forces
Nonconservative forces, unlike conservative ones, depend on the path an object takes. In our problem, friction is a prime example of a nonconservative force. Such forces convert mechanical energy into other forms of energy, like heat. Consider a box traveling in a circular path: the work done by friction is calculated based on the entire path's length, not just the initial and final positions, indicating its nonconservative nature.

When dealing with nonconservative forces, energy is often lost to the environment, making these forces critical in energy analysis. This is why knowing whether a force like friction is conservative or nonconservative affects how we approach physics problems. It informs us about energy conservation's limitations in mechanical systems, providing insights into real-world applications where energy efficiency matters.
Circular Motion
Circular motion involves an object moving in a path shaped like a circle. This movement is characterized by constant change in direction, but not necessarily in speed. In our scenario, the box on a circular path experiences friction throughout its motion, affecting how we calculate work.

The complete circular distance is the circumference of the circle, given by:
  • \[ d = 2\pi r \]
where \( r \) is the radius. This relationship helps find the total work done by friction over one full loop. Circular motion is not just about moving around a path; it's about understanding forces like friction that act during motion. It explains how rotation impacts energy expenditure, making learners appreciate the complexities of rotational systems.
Physics Problem Solving
Physics problem solving involves breaking down complex situations into manageable parts to find a solution. In our exercise, we followed specific steps:
  • Understand the work done by friction for cyclical motion.
  • Calculate the kinetic friction force using the coefficient of friction and normal force.
  • Determine the work done by calculating the distance over the circular path.
  • Analyze the nature of friction as a nonconservative force.
Each step builds on the previous, ensuring a clear path from the problem's statement to the solution. This structured approach not only aids in solving physics questions but also enhances critical thinking and analytical skills needed in many technical fields. By mastering these steps, students learn to approach various physics problems effectively, grounding their understanding in fundamental principles.

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Most popular questions from this chapter

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