/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 6 A crate of mass \(M\) starts fro... [FREE SOLUTION] | 91Ó°ÊÓ

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A crate of mass \(M\) starts from rest at the top of a frictionless ramp inclined at an angle \(\alpha\) above the horizontal. Find its speed at the bottom of the ramp, a distance \(d\) from where it started. Do this in two ways: (a) Take the level at which the potential energy is zero to be at the bottom of the ramp with y positive upward.(b) Take the zero level for potential energy to be at the top of the ramp with \(y\) positive upward. (c) Why did the normal force not enter into your solution?

Short Answer

Expert verified
The speed of the crate at the bottom is \( \sqrt{2g d \sin(\alpha)} \). The normal force does no work because it is perpendicular to the motion.

Step by step solution

01

Determine Initial Conditions

First, recognize that the crate starts from rest, so its initial kinetic energy, \( KE_0 \), is 0. The potential energy depends on the height, which we'll calculate next.
02

Calculate the Height of the Ramp

Since the ramp is inclined at an angle \( \alpha \) and the crate travels a distance \( d \), the height \( h \) of the ramp is given by the relation: \( h = d \sin(\alpha) \).
03

Solution (a) – Energy Conservation at the Bottom

When using the bottom of the ramp as the reference point for potential energy, the potential energy at the top is \( PE_0 = Mg h = Mg d \sin(\alpha) \). At the bottom, all potential energy is converted into kinetic energy. Using energy conservation: \[ Mg d \sin(\alpha) = \frac{1}{2} M v^2 \] Solving for \( v \), we have: \[ v = \sqrt{2g d \sin(\alpha)} \]
04

Solution (b) – Energy Conservation at the Top

If the zero level for potential energy is at the top, then initial potential energy \( PE_0 \) is 0, and the potential energy at the bottom is \( PE_1 = -Mg d \sin(\alpha) \). By energy conservation, this means the kinetic energy gained \( KE_1 \) at the bottom is \(-Mg d \sin(\alpha)\), so: \[ \frac{1}{2} M v^2 = Mg d \sin(\alpha) \] Solving for \( v \), the result is the same: \[ v = \sqrt{2g d \sin(\alpha)} \]
05

Explanation (c) – Role of the Normal Force

The normal force is perpendicular to the motion of the crate. It does no work because work is calculated as \( W = F \cdot d \cdot \cos(\theta) \), and here \( \theta = 90^\circ \) (meaning \( \cos(90^\circ) = 0 \)), resulting in zero work done by the normal force.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Potential Energy
Potential energy is the energy that an object possesses due to its position in a gravitational field. In this exercise, the crate initially has potential energy because it is located at the top of an inclined plane. Potential energy is calculated using the formula: \[ PE = mgh \] where:
  • \(m\) is the mass of the crate,
  • \(g\) is the acceleration due to gravity (approximately \(9.81\, m/s^2\) on Earth), and
  • \(h\) is the height above the reference point.
In part (a), the zero level for potential energy is considered at the bottom of the ramp. Therefore, the height \(h\) is calculated as \(d \sin(\alpha)\), where \(d\) is the distance along the ramp and \(\alpha\) is the angle of incline. At the top, the potential energy is \( Mg d \sin(\alpha)\). When the crate reaches the bottom, its height is zero, and so is its potential energy.
Kinetic Energy
Kinetic energy is the energy of motion. The crate, initially at the top of the incline, starts from rest, meaning its initial kinetic energy is zero. As it moves down the plane, its potential energy converts into kinetic energy. The kinetic energy of an object is given by the formula: \[ KE = \frac{1}{2} mv^2 \] where:
  • \(m\) is the mass of the object, and
  • \(v\) is its velocity.
At the bottom of the ramp, all the initial potential energy (calculated when using the bottom as a reference) has converted into kinetic energy, allowing you to solve for \(v\). This helps us find the speed of the crate at the bottom of the ramp using the transformation of energy states.
Energy Conservation
Energy conservation is a key principle of mechanics stating that energy cannot be created or destroyed; it can only change from one form to another. In this inclined plane problem, we see energy conservation through the transformation of potential energy into kinetic energy.Utilizing energy conservation, you first determine the potential energy at the top and equate it to the kinetic energy at the bottom. With either reference point for potential energy from parts (a) or (b), the result for the speed \(v\) doesn't change because the difference in energy between the top and the bottom remains constant. This demonstrates that regardless of where the zero level for potential energy is set, the physics of the situation, as illustrated by the principle of energy conservation, remains unchanged.
Inclined Plane
An inclined plane is a flat surface tilted at an angle to the horizontal, which facilitates understanding fundamental mechanics concepts such as forces and energy transformation. In this problem, the ramp forms an angle \(\alpha\) with the horizontal.Inclined planes help break down forces into components:
  • The gravitational force component \(mg\sin(\alpha)\) acts parallel to the plane, causing motion.
  • The normal force, which acts perpendicular, executes no work, since its direction is always perpendicular to the direction of movement.
Understanding these components allows us to set up problems involving energy changes on inclines without needing to consider the normal force's work, simplifying the energy calculations.

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