/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 9 A box rests on a frozen pond, wh... [FREE SOLUTION] | 91Ó°ÊÓ

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A box rests on a frozen pond, which serves as a frictionless horizontal surface. If a fisherman applies a horizontal force with magnitude 48.0 \(\mathrm{N}\) to the box and produces an acceleration of mag-nitude \(3,00 \mathrm{m} / \mathrm{s}^{2},\) what is the mass of the box?

Short Answer

Expert verified
The mass of the box is 16.0 kg.

Step by step solution

01

Identify the Given Values

We have the force applied to the box, which is 48.0 N, and the acceleration produced, which is 3.00 m/s². Our goal is to find the mass of the box.
02

Apply Newton's Second Law

Newton's Second Law states: \( F = ma \) where \( F \) is the force applied to the box, \( m \) is the mass of the box, and \( a \) is the acceleration. Rearrange the equation to solve for \( m \): \( m = \frac{F}{a} \).
03

Substitute the Given Values

Substitute the given values into the equation to find the mass: \( m = \frac{48.0 \: \mathrm{N}}{3.00 \: \mathrm{m/s}^2} \).
04

Calculate the Mass

Perform the division: \( m = \frac{48.0}{3.00} = 16.0 \). The mass of the box is 16.0 kg.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Force and Acceleration
When understanding **Newton's Second Law**, it's important to grasp how force and acceleration are connected. This law tells us that the force applied on an object is equal to the mass of the object multiplied by its acceleration. The formula is:\[ F = ma \]Here:
  • \( F \) stands for the force applied, measured in Newtons (N).
  • \( m \) is the mass, which we aim to find in this problem.
  • \( a \) is the acceleration, measured in meters per second squared (m/s²).
When a force is applied to an object like the box in our problem, it causes the box to accelerate in the direction of that force. The greater the force, the greater the acceleration, provided the mass remains constant. Conversely, for the same force, a more massive object will accelerate less compared to a lighter one. This relationship is crucial for solving physics problems dealing with motion.
Mass Calculation
**Calculating mass** becomes straightforward using Newton's Second Law when given force and acceleration. All we need to do is rearrange the original formula \( F = ma \) to solve for the object's mass. The rearrangement goes like this:\[ m = \frac{F}{a} \]By substituting the given values from our exercise:
  • Force \( F = 48.0 \, \mathrm{N} \)
  • Acceleration \( a = 3.00 \, \mathrm{m/s}^2 \)
We plug these numbers into our mass formula:\[ m = \frac{48.0 \, \mathrm{N}}{3.00 \, \mathrm{m/s}^2} \]And we find:\[ m = 16.0 \, \mathrm{kg} \]This calculation reveals that the box has a mass of 16.0 kilograms. Using these straightforward steps helps verify that our comprehension of Newton's law holds, establishing a solid foundation for tackling more complex physics puzzles.
Frictionless Surface
A **frictionless surface** is an ideal scenario often used in physics problems to simplify calculations. In reality, most surfaces exert some resistance against moving objects, known as friction. But in our exercise, considering a frozen pond as a frictionless horizontal surface, means this resistance is non-existent. This absence impacts motion, as it allows the force applied to wholly convert into movement without any loss. Without friction, there is no opposing force to counteract the applied force. Hence, all of the applied 48.0 N can be utilized to induce the motion of the box. This setup helps us directly observe the effect of force on an object, accentuating the principles outlined in Newton's Second Law. It also facilitates the calculations by eliminating any need to consider frictional forces, thus focusing purely on force, mass, and acceleration.

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Most popular questions from this chapter

Human Biomechanics. The fastest pitched baseball was measured at 46 \(\mathrm{m} / \mathrm{s}\) . Typically, a baseball has a mass of 145 \(\mathrm{g}\) . If the pitcher exerted his force (assumed to be horizontal and constant) over a distance of \(1.0 \mathrm{m},(\mathrm{a})\) what force did he produce on the ball during this record-setting pitch? (b) Draw free-body diagrams of the ball during the pitch and just after it left the pitcher's hand.

A 68.5 -kg skater moving initially at 2.40 \(\mathrm{m} / \mathrm{s}\) on rough horizontal ice comes to rest uniformly in 3.52 s due to friction from the ice. What force does friction exert on the skater?

A.22 rifle bullet, traveling at \(350 \mathrm{m} / \mathrm{s},\) strikes a large tree, which it penetrates to a depth of 0.130 \(\mathrm{m} .\) The mass of the bullet is 1.80 g. Assume a constant retarding force. (a) How much time is required for the bullet to stop? (b) What force, in newtons, does the tree exert on the bullet?

Two horses pull horizontally on ropes attached to a stump. The two forces \(\vec{F}_{1}\) and \(\vec{F}_{2}\) that they apply to the stump are such that the net (resultant) force \(\vec{R}\) has a magnitude equal to that of \(\vec{\boldsymbol{F}}_{1}\) and makes an angle of \(90^{\circ}\) with \(\vec{\boldsymbol{F}}_{1 .}\) Let \(F_{1}=1300 \mathrm{N}\) and \(R=1300 \mathrm{N}\) also. Find the magnitude of \(\vec{\boldsymbol{F}}_{2}\) and its direction \((\mathrm{rela}-\)tive to \(\vec{\boldsymbol{F}}_{1} ).\)

Superman throws a 2400 -N boulder at an adversary. What horizontal force must Superman apply to the boulder to give it a horizontal acceleration of 12.0 \(\mathrm{m} / \mathrm{s}^{2}\) ?

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