/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 17 Superman throws a 2400 -N boulde... [FREE SOLUTION] | 91Ó°ÊÓ

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Superman throws a 2400 -N boulder at an adversary. What horizontal force must Superman apply to the boulder to give it a horizontal acceleration of 12.0 \(\mathrm{m} / \mathrm{s}^{2}\) ?

Short Answer

Expert verified
The horizontal force applied by Superman is approximately 2940 N.

Step by step solution

01

Identify Given Values

We are given the weight of the boulder as 2400 N and the horizontal acceleration as 12.0 m/s².
02

Understand the Problem

We need to calculate the horizontal force required to accelerate the boulder at 12.0 m/s².
03

Use Newton's Second Law

According to Newton's second law, the force needed to accelerate an object can be calculated using the formula: \[ F = m \cdot a \]where \( F \) is the force, \( m \) is the mass of the object, and \( a \) is the acceleration.
04

Calculate the Mass of the Boulder

The weight of the boulder is given as 2400 N, which is the force of gravity acting on it. The weight \( W \) is related to mass \( m \) by:\[ W = m \cdot g \]Given that \( g = 9.8 \text{ m/s}^2 \), we can rearrange to find \( m \):\[ m = \frac{W}{g} = \frac{2400}{9.8} \approx 244.9 \text{ kg} \].
05

Substitute and Calculate Force

Now, substitute \( m = 244.9 \text{ kg} \) and \( a = 12.0 \text{ m/s}^2 \) in the Newton's second law formula:\[ F = 244.9 \cdot 12.0 = 2938.8 \text{ N} \].
06

Round the Final Answer

It's appropriate to round the final answer to three significant figures like the given numbers:\[ F \approx 2940 \text{ N} \].

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Horizontal Force Calculation
Calculating horizontal force involves using the basic principles of physics, specifically Newton's Second Law of Motion. When you want to find out how much force an object requires to accelerate over a surface horizontally, you apply the formula \[ F = m \cdot a \] This means that the force \( F \) is equal to the mass of the object \( m \) times the acceleration \( a \) you want the object to achieve. In a practical example like Superman throwing a boulder, knowing the acceleration desired (12.0 m/s² here) allows you to determine the exact force Superman needs to apply, once you have the mass.
Understanding this concept is crucial for solving problems where you have to deal with movement or acceleration in a controlled manner. By focusing on the force required, you're tapping into one of the most fundamental aspects of physics, connecting the theoretical frameworks to real-world interactions.
Mass and Weight Relationship
The relationship between mass and weight may seem confusing at first, but it becomes clear once you know that weight is simply the force exerted by gravity on an object. It is mathematically expressed as \[ W = m \cdot g \] where \( W \) is the weight, \( m \) is the mass, and \( g \) is the acceleration due to gravity, which is approximately 9.8 m/s² on Earth.
If you know the weight of an object, like the 2400 N boulder Superman has to throw, you can find its mass by rearranging the formula to \[ m = \frac{W}{g} \] In this exact problem, this calculation would give us a mass of about 244.9 kg.
Understanding this relationship is vital because it allows you to switch between weight and mass, a skill you'll need in many physical science problems. This relationship tells you how an object will behave under the force of gravity, which is an essential concept when discussing various forces acting on a body.
Significant Figures Rounding
Significant figures are essential when reporting scientific measurements because they reflect the precision of your data. When doing calculations like the force required for Superman to throw the boulder, each value in the calculation has a certain precision based on the context.
  • The original weight of 2400 N and acceleration of 12.0 m/s² indicate their measurements carry three significant figures.
  • When Superman applies the calculated force, this precision impacts the rounding of the result.
After computing the force as 2938.8 N, rounding conservatively to three significant figures (as shown by the less precise original measurements) gives you 2940 N.
Mastering the use of significant figures ensures clarity and accuracy in communication, reducing errors in scientific calculations and findings. When you round your answer correctly, you communicate the precision level of your measurements effectively, which is crucial in scientific and engineering tasks.

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Most popular questions from this chapter

Human Biomechanics. The fastest pitched baseball was measured at 46 \(\mathrm{m} / \mathrm{s}\) . Typically, a baseball has a mass of 145 \(\mathrm{g}\) . If the pitcher exerted his force (assumed to be horizontal and constant) over a distance of \(1.0 \mathrm{m},(\mathrm{a})\) what force did he produce on the ball during this record-setting pitch? (b) Draw free-body diagrams of the ball during the pitch and just after it left the pitcher's hand.

To study damage to aircraft that collide with large birds, you design a test gun that will accelerate chicken-sized objects so that their displacement along the gun barrel is given by \(x=\left(9.0 \times 10^{3} \mathrm{m} / \mathrm{s}^{2}\right) t^{2}-\left(8.0 \times 10^{4} \mathrm{m} / \mathrm{s}^{3}\right) t^{3} .\) The object leaves the end of the barrel at \(t=0.025\) s. (a) How long must the gun barrel be? (b) What will be speed of the objects as they leave the end of the barrel? (c) What net force must be exerted on a 1.50 -kg object at (i) \(t=0\) and (ii) \(t=0.025\) s?

Two forces, \(\vec{\boldsymbol{F}}_{1}\) and \(\vec{\boldsymbol{F}}_{2},\) a point. The magnitude of \(\vec{\boldsymbol{F}}_{1}\) is \(9.00 \mathrm{N},\) and its direction is \(60.0^{\circ}\) above the \(x\) -axis in the second quadrant. The magnitude of \(\vec{\boldsymbol{F}}_{2}\) is \(6.00 \mathrm{N},\) and its direction is \(53.1^{\circ}\) below the \(x\) -axis in the third quadrant. (a) What are the \(x\) - and \(y\) -components of the resultant force? (b) What is the magnitude of the resultant force?

You walk into an elevator, step onto a scale, and push the "up" button. You also recall that your normal weight is 625 \(\mathrm{N}\) . Start answering each of the following questions by drawing a free-body diagram. (a) If the elevator has an acceleration of magnitude \(2.50 \mathrm{m} / \mathrm{s}^{2},\) what does the scale read? (b) If you start holding a 3.85 -kg package by a light vertical string, what will be the tension in this string once the elevator begins accelerating?

\(\mathrm{A}\) man is dragging a trunk up the loading ramp of a mover's truck. The ramp has a a slope angle of \(20.0^{\circ}\) , and the man pulls upward with a force \(\vec{F}\) whose direction makes an angle of \(30.0^{\circ}\) with the ramp (Fig. E4.4). (a) How large a force \(\vec{F}\) is necessary for the component \(F_{x}\) parallel to the ramp to be 60.0 \(\mathrm{N} ?\) (b) How large will the component \(F_{y}\) perpendicular to the ramp then be?

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