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What is the de Broglie wavelength of a red blood cell, with mass \(1.00 \times 10^{-11} \mathrm{g}\) , that is moving with a speed of 0.400 \(\mathrm{cm} / \mathrm{s} ?\) Do we need to be concerned with the wave nature of the blood cells when we describe the flow of blood in the body?

Short Answer

Expert verified
The de Broglie wavelength is \(1.6565 \times 10^{-17} \text{m}\); wave nature of blood cells can be ignored in practical biological contexts.

Step by step solution

01

Understand the de Broglie wavelength formula

The de Broglie wavelength is given by the formula \( \lambda = \frac{h}{mv} \), where \( \lambda \) is the wavelength, \( h \) is Planck's constant \( 6.626 \times 10^{-34} \, \text{m}^2 \text{kg/s} \), \( m \) is the mass of the object, and \( v \) is its velocity.
02

Convert units of mass and velocity

First, convert the mass and velocity to SI units. The mass of the red blood cell is \(1.00 \times 10^{-11} \, \text{g} = 1.00 \times 10^{-14} \, \text{kg}\). The velocity is \(0.400 \, \text{cm/s} = 0.004 \, \text{m/s}\).
03

Plug values into the de Broglie equation

Substitute the known values into the de Broglie formula: \( \lambda = \frac{6.626 \times 10^{-34} \, \text{m}^2 \text{kg/s}}{1.00 \times 10^{-14} \, \text{kg} \times 0.004 \text{m/s}}\).
04

Calculate the de Broglie wavelength

Perform the calculation to find the wavelength: \( \lambda = \frac{6.626 \times 10^{-34}}{4 \times 10^{-17}} \). Simplifying this gives \( \lambda = 1.6565 \times 10^{-17} \, \text{m} \).
05

Conclusion on wave nature

The calculated de Broglie wavelength of the red blood cell is extremely small (on the order of \(10^{-17} \text{m}\)), which is much smaller than the size of a typical red blood cell or other biological structures. Therefore, this wavelength does not have any observable effects on how blood flows in the body.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Planck's constant
Planck's constant, denoted as \( h \), is a fundamental constant in physics, central to the theory of quantum mechanics. Its value is approximately \( 6.626 \times 10^{-34} \text{ m}^2 \text{ kg/s} \). This constant relates the energy of a photon to its frequency and is essential when considering particles at a quantum level. It bridges the gap between the wave and particle nature of light, allowing us to calculate phenomena such as the de Broglie wavelength. In this context, it is used to determine the wavelength associated with a moving particle, like a red blood cell, using the formula \( \lambda = \frac{h}{mv} \). This formula shows that the wavelength (\( \lambda \)) decreases as mass (\( m \)) or velocity (\( v \)) increases, making high-velocity particles with substantial mass, like red blood cells, possess imperceptibly small wavelengths.

Understanding Planck's constant is crucial for recognizing the quantized nature of microscopic processes, which are not apparent in our everyday macroscopic world.
Wave-particle duality
Wave-particle duality is a core concept of quantum mechanics, describing how every particle or quantum entity can exhibit both wave and particle properties. It was introduced by Louis de Broglie, who proposed that particles typically thought of as having mass, such as electrons and protons, also possess an associated wave-like behavior. This idea is foundational to understanding phenomena that cannot be explained by classical physics alone.

For example, light demonstrates wave-like behavior in diffraction and interference, yet it behaves like a particle in the photoelectric effect, where it ejects electrons from a metal surface. The de Broglie wavelength formula we use for the red blood cell in this exercise stems from this dual nature, highlighting why physicists originally turned to this concept to explain behaviors on the quantum scale.

The concept doesn't significantly affect heavy and slow-moving objects like red blood cells because their computed wavelengths are extremely small, making any wave-like properties essentially unobservable. However, it is crucial in understanding and predicting the behavior of subatomic particles.
SI units conversion
SI units, or the International System of Units, are the globally accepted standard for scientific measurements, enabling clear communication and consistent calculations across various fields. In the context of physics problems involving the de Broglie wavelength, converting quantities like mass and velocity into SI units ensures accuracy and consistency.

For example, the mass of the red blood cell in the exercise is initially given in grams. To convert to kilograms, the standard SI unit for mass, you multiply by \(10^{-3}\). Similarly, speed is given in centimeters per second and must be converted to meters per second, the SI unit for velocity, by dividing by 100.

The importance of using SI units cannot be overstated. Without this conversion, the calculation of the de Broglie wavelength could be incorrect, potentially leading to incorrect conclusions about the nature of the wave-like behavior of particles. By ensuring all measurements are in SI units, we maintain the integrity and reliability of scientific calculations and results.

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Most popular questions from this chapter

(a)A particle with mass \(m\) has kinetic energy equal to three times its rest energy. What is the de Broglie wavelength of this particle? (Hint: You must use the relativistic expressions for momentum and kinetic energy: \(E^{2}=(p c)^{2}+\left(m c^{2}\right)^{2}\) and \(K=\) \(E-m c^{2} \cdot )\) (b) Determine the numerical value of the kinetic energy (in MeV) and the wavelength (in meters) if the particle in part (a) is (i) an electron and (ii) a proton.

Radiation has been detected from space that is characteristic of an ideal radiator at \(T=2.728 \mathrm{K}\) . This radiation is a relic of the Big Big Bang at the beginning of the universe.) For this temperature, at what wavelength does the Planck distribution peak? In what part of the electromagnetic spectrum is this wavelength?

A beam of alpha particles is incident on a target of lead. A particular alpha particle comes in "head-on" to a particular lead nucleus and stops \(6.50 \times 10^{-14} \mathrm{m}\) away from the center of the nucleus. This point is well outside the nucleus. Assume that the lead nucleus, which has 82 protons, remains at rest. The mass of the alpha particle is \(6.64 \times 10^{-27}\) kg. (a) Calculate the electrostatic potential energy at the instant that the alpha particle stops. Express your result in joules and in MeV. (b) What initial kinetic energy (in joules and in MeV) did the alpha particle have? (c) What was the initial speed of the alpha particle?

Two stars, both of which behave like ideal black bodies, radiate the same total energy per second. The cooler one has a surface temperature \(T\) and a diameter 3.0 times that of the hotter star. (a) What is the temperature of the hotter star in terms of \(T ?\) (b) What is the ratio of the peak-intensity wavelength of the hot star to the peak-intensity wavelength of the cool star?

Find the longest and shortest wavelengths in the Lyman and Paschen series for hydrogen. In what region of the electromagnetic spectrum does each series lie?

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