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Radiation has been detected from space that is characteristic of an ideal radiator at \(T=2.728 \mathrm{K}\) . This radiation is a relic of the Big Big Bang at the beginning of the universe.) For this temperature, at what wavelength does the Planck distribution peak? In what part of the electromagnetic spectrum is this wavelength?

Short Answer

Expert verified
The peak wavelength is approximately 1062 micrometers, in the microwave region.

Step by step solution

01

Understand Wien's Displacement Law

Wien's Displacement Law relates the peak wavelength of radiation from a black body to its temperature. It is given by \( \lambda_{max} = \frac{b}{T} \), where \( \lambda_{max} \) is the peak wavelength, \( b \) is Wien's constant \((2.897 \times 10^{-3} \, \text{m} \cdot \text{K})\), and \( T \) is the temperature in Kelvin.
02

Apply Wien's Displacement Law

Using Wien's Displacement Law, substitute the given temperature \( T = 2.728 \, \text{K} \) into the formula: \[ \lambda_{max} = \frac{2.897 \times 10^{-3} \, \text{m} \cdot \text{K}}{2.728 \, \text{K}} \].
03

Perform the Calculation

Calculate the peak wavelength: \[ \lambda_{max} = \frac{2.897 \times 10^{-3} \, \text{m} \cdot \text{K}}{2.728 \, \text{K}} \approx 1.062 \times 10^{-3} \, \text{m} \]. This is approximately 1062 micrometers.
04

Determine the Spectrum Region

Identify the part of the electromagnetic spectrum corresponding to 1062 micrometers. Since this wavelength is in the range of 1 millimeter, it falls within the microwave region of the electromagnetic spectrum.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Wien's Displacement Law
Wien's Displacement Law is a fundamental principle in thermal physics that explains how the peak wavelength of radiation emitted by a black body shifts with temperature. Essentially, this law states that as the temperature of the black body increases, the peak wavelength of the emitted radiation becomes shorter. It is an inverse relationship. This can be captured through the formula:
  • \( \lambda_{max} = \frac{b}{T} \)
  • \( \lambda_{max} \) is the peak wavelength in meters,
  • \( b \) is Wien's constant, approximately \(2.897 \times 10^{-3} \, \text{m} \cdot \text{K}\),
  • and \( T \) is the temperature in Kelvin.
The law provides a straightforward way to calculate the point in the spectrum where the radiation from a black body is most intense. For instance, a hotter star would peak in the blue or ultraviolet part of the spectrum, while a cooler one might peak in the red or infrared region. This principle is a key tool in astrophysics for determining the temperatures of distant objects based simply on their emitted light's peak wavelength.
Black Body Radiation
Black body radiation is a type of electromagnetic radiation emitted by a perfect absorber of energy, known as a black body. A black body absorbs all incident radiation regardless of frequency or angle of incidence, and it also emits radiation based solely on its temperature. The concept of a black body is theoretical, but many real objects approximate black bodies quite closely. Some important aspects of black body radiation include:
  • It serves as a model for the emission of thermal radiation.
  • The radiation emitted by a black body is continuous over a range of wavelengths.
  • The intensity of radiation emitted at each wavelength increases with temperature.
Black body radiation is fundamental to understanding the thermal characteristics of stars and planets. The study of this radiation laid the groundwork for quantum mechanics, and helped in the development of Planck's law, which describes how the intensity of black body radiation is distributed across different wavelengths at a given temperature.
Planck Distribution
The Planck distribution provides a detailed description of the spectral energy distribution of electromagnetic radiation emitted by a black body in thermal equilibrium at a given temperature. It marks a significant breakthrough in physics, offering a solution to the ultraviolet catastrophe predicted by classical physics.Planck's law states that the energy emitted per unit area, per unit time, per unit frequency, is given by:
  • \[ E(u, T) = \frac{8\pi h u^3}{c^3} \cdot \frac{1}{e^{\frac{hu}{kT}} - 1} \]
  • where \( E(u, T) \) is the spectral energy density,
  • \( u \) is the frequency, \( h \) is Planck's constant,
  • \( c \) is the speed of light, \( k \) is Boltzmann's constant,
  • and \( T \) is the temperature in Kelvin.
This complex equation explains that the intensity of the radiation depends on the frequency of the electromagnetic wave and the temperature of the black body. Planck's distribution also aids in calculating the "peak wavelength鈥 with tools such as Wien's displacement law, which we covered earlier. This concept is essential not just in understanding theoretical physics but also in practical applications like designing thermal cameras and understanding cosmic microwave background radiation.

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Most popular questions from this chapter

A certain atom has an energy level 3.50 eV above the ground state. When excited to this state, it remains \(4.0 \mu s,\) on the average, before emitting a photon and returning to the ground average, before emitting a photon and returning to the ground state. (a) What is the energy of the photon? What is its wavelength? (b) What is the smallest possible uncertainty in energy of the photon?

An atom with mass \(m\) emits a photon of wavelength \(\lambda\) . (a) What is the recoil speed of the atom? (b) What is the kinetic energy \(K\) of the recoiling atom? (c) Find the ratio \(K / E,\) where \(E\) is the energy of the emitted photon. If this ratio is much less than unity, the recoil of the atom can be neglected in the emission process. Is the recoil of the atom more important for small or large atomic masses? For long or short wavelengths? (d) Calculate \(K\) (in electron volts) and \(K / E\) for a hydrogen atom (mass \(1.67 \times\) \(10^{-27} \mathrm{kg} )\) that emits an ultraviolet photon of energy 10.2 eV. Is recoil an important consideration in this emission process?

A beam of electrons is accelerated from rest through a potential difference of 0.100 \(\mathrm{kV}\) and then passes through a thin slit. The diffracted beam shows its first diffraction minima at \(\pm 11.5^{\circ}\) from the original direction of the beam when viewed far from the slit. (a) Do we need to use relativity formulas? How do you know? (b) How wide is the slit?

A sample of hydrogen atoms is irradiated with light with wavelength \(85.5 \mathrm{nm},\) and electrons are observed leaving the gas. (a) If each hydrogen atom were initially in its ground level, what would be the maximum kinetic energy in electron volts of these photoelectrons? (b) A few electrons are detected with energies as much as 10.2 eV greater than the maximum kinetic energy calculated in part (a). How can this be?

Why Don't \(W e\) Diffract? (a) Calculate the de Broglie wavelength of a typical person walking through a doorway. Make reasonable approximations for the necessary quantities. (b) Will the person in part (a) exhibit wavelike behavior when walking through the "single slit" of a doorway? Why?

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