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(a) What is the smallest amount of energy in electron volts that must be given to a hydrogen atom initially in its ground level so that it can emit the \(H_{\alpha}\) line in the Balmer series? (b) How many different possibilities of spectral-line emissions are there for this atom when the electron starts in the \(n=3\) level and eventually ends up in the ground level? Calculate the wavelength of the emitted photon in each case.

Short Answer

Expert verified
(a) 12.09 eV is required to emit \(H_{\alpha}\). (b) There are 3 emission possibilities from \(n=3\) to \(n=1\).

Step by step solution

01

Understanding the Exercise

First, we need to find the smallest energy required to excite a hydrogen atom from its ground level (n=1) to a level that allows it to emit the \(H_{\alpha}\) line. The \(H_{\alpha}\) line occurs during a transition from \(n=3\) to \(n=2\). This means the hydrogen atom must be excited to at least \(n=3\).
02

Calculating the Energy Required to Reach n=3

To find the energy required to excite the atom from the ground state \(n=1\) to \(n=3\), we use the formula for the energy levels of hydrogen: \(E_n = - 13.6 \text{ eV} / n^2\). Calculate \(E_1\) and \(E_3\): - For \(n=1\), \(E_1 = - 13.6 \text{ eV}\).- For \(n=3\), \(E_3 = - 13.6/9 \text{ eV} = -1.51 \text{ eV}\).The energy required to excite to \(n=3\) from \(n=1\) is \(E = E_3 - E_1 = -1.51 + 13.6 = 12.09 \text{ eV}\).
03

Different Spectral-Line Emissions from n=3

If the electron is starting from the \(n=3\) level and going to the \(n=1\) level, it can take several paths. The possible transitions are: 1. \(3 \rightarrow 2\)2. \(3 \rightarrow 1\)3. \(2 \rightarrow 1\)These paths correspond to the possible spectral-line emissions.
04

Calculating the Wavelength for Each Transition

We use the formula for the wavelength \(\lambda\) of the photon: \(\frac{1}{\lambda} = R_H \left( \frac{1}{n_1^2} - \frac{1}{n_2^2} \right)\), where \(R_H = 1.097 \times 10^7 \text{ m}^{-1}\).- For \(3 \rightarrow 2\): \(\frac{1}{\lambda} = 1.097 \times 10^7 \left( \frac{1}{2^2} - \frac{1}{3^2} \right)\). Calculate \(\lambda\). - For \(3 \rightarrow 1\): \(\frac{1}{\lambda} = 1.097 \times 10^7 \left( 1 - \frac{1}{3^2} \right)\). Calculate \(\lambda\). - For \(2 \rightarrow 1\): \(\frac{1}{\lambda} = 1.097 \times 10^7 \left( 1 - \frac{1}{2^2} \right)\). Calculate \(\lambda\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Balmer series
The Balmer series is a sequence of spectral lines in the visible region of the hydrogen atom's emission spectrum. Johannes Balmer discovered this series in 1885 by observing the spectral lines of hydrogen. These lines occur when an electron transitions to the second energy level, also known as the Balmer series' final state. For hydrogen, the series includes many visible spectral lines, each representing a photon emitted during an electron's transition from a higher energy level.

The Balmer series is essential because it lies within the visible light spectrum. The primary transitions include:
  • From the third energy level to the second (producing the red Hα line)
  • From the fourth to the second (producing the blue-green Hβ line)
  • Other lines continue in higher frequencies
Understanding the Balmer series helps us study the quantum mechanics of atoms and deduce their properties, such as electron configuration and energy states.
spectral line emissions
Spectral line emissions occur when electrons move between energy levels within an atom. Specifically, when an electron jumps from a higher to a lower energy level, it releases energy in the form of a photon. This photon contributes to the unique spectral lines characteristic of each element.

In hydrogen atoms, distinct spectral line emissions are observed when electrons transition between different quantized energy levels. From the initial level, called the excited state, the electron drops down to a lower energy level, or the ground state. This shift produces various emissions, which appear as lines in the spectrum.

For example, when a hydrogen atom's electron transitions from an energy level of n=3 to n=2, it produces the Balmer Hα line. Spectral lines serve as fingerprints, helping scientists identify atomic structures and composition of substances.
wavelength of photon
The wavelength of a photon emitted during an electron transition is crucial for understanding the nature of that transition. Wavelength is inversely related to the energy of the photon; thus, higher energy transitions result in shorter wavelengths.

To determine the wavelength of a photon, we use the Rydberg formula:\[\frac{1}{\lambda} = R_H \left( \frac{1}{n_1^2} - \frac{1}{n_2^2} \right)\]Where:
  • \( \lambda \) is the wavelength
  • \( R_H \) is the Rydberg constant, approximately \( 1.097 \times 10^7 \text{ m}^{-1} \)
  • \( n_1 \) and \( n_2 \) are the principal quantum numbers of the lower and higher energy levels
By applying this formula to different transitions, we can calculate the wavelength emitted. This understanding allows us to link observed spectral lines to their corresponding electron transitions.

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Most popular questions from this chapter

A CD-ROM is used instead of a crystal in an electron- diffraction experiment. The surface of the CD-ROM has tracks of tiny pits with a uniform spacing of 1.60\(\mu \mathrm{m} .\) (a) If the speed of the electrons is \(1.26 \times 10^{4} \mathrm{m} / \mathrm{s},\) at which values of \(\theta\) will the \(m=1\) and \(m=2\) intensity maxima appear? (b) The scattered electrons in these maxima strike at normal incidence a piece of photographic film that is 50.0 \(\mathrm{cm}\) from the CD-ROM. What is the spacing on the film between these maxima?

Blue Supergiants. A typical blue supergiant star (the type that explodes and leaves behind a black hole) has a surface temperature of \(30,000 \mathrm{K}\) and a visual luminosity \(100,000\) times that of our sun. Our sun radiates at the rate of \(3.86 \times 10^{26} \mathrm{W}\) .(Visual luminosity is the total power radiated at visible wavelengths.) (a) Assuming that this star behaves like an ideal blackbody, what is the principal wavelength it radiates? Is this light visible? Use your answer to explain why these stars are blue. (b) If we assume that the power radiated by the star is also \(100,000\) times that of our sun, what is the radius of this star? Compare its size to that of our sun, which has a radius of \(6.96 \times 10^{5} \mathrm{km}\) . (c) Is it really correct to say that the visual luminosity is proportional to the total power radiated? Explain.

Imagine another universe in which the value of Planck's constant is 0.0663 \(\mathrm{J} \cdot \mathrm{s}\) , but in which the physical laws and all other physical constants are the same as in our universe. In this universe, two physics students are playing catch. They are 12 \(\mathrm{m}\) apart, and one throws a 0.25 -kg ball directly toward the other with a speed of 6.0 \(\mathrm{m} / \mathrm{s} .\) (a) What is the uncertainty in the ball's horizontal momentum, in a direction perpendicular to that in which it is being thrown, if the student throwing the ball knows that it is located within a cube with volume 125 \(\mathrm{cm}^{3}\) at the time she throws it? (b) By what horizontal distance could the ball miss the second student?

Suppose that the uncertainty of position of an electron is equal to the radius of the \(n=1\) Bohr orbit for hydrogen. Calculate the simultaneous minimum uncertainty of the corresponding momentum component, and compare this with the magnitude of the momentum of the electron in the \(n=1\) Bohr orbit. Discuss your results.

A hydrogen atom initially in the ground level absorbs a photon, which excites it to the \(n=4\) level. Determine the wavelength and frequency of the photon.

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