/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 25 A hydrogen atom is in a state wi... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A hydrogen atom is in a state with energy \(-1.51 \mathrm{eV}\) . In the Bohr model, what is the angular momentum of the electron in the atom, with respect to an axis at the nucleus?

Short Answer

Expert verified
The angular momentum of the electron is approximately \( 3.165 \times 10^{-34} \text{ J s} \).

Step by step solution

01

Stating the Energy Level Formula for Hydrogen Atom

To determine the quantized energy of an electron in a hydrogen atom, we use the Bohr model, which states that the energy of an electron in an orbit is given by \[ E_n = -\frac{13.6 \, \text{eV}}{n^2} \]where \( E_n \) is the energy and \( n \) is the principal quantum number, which must be an integer.
02

Solve for Principal Quantum Number n

Given the energy of the electron is \(-1.51 \, \text{eV}\), we set \[-\frac{13.6}{n^2} = -1.51\] and solve for \( n \):\[ n^2 = \frac{13.6}{1.51} \approx 8.993\]\[ n \approx \sqrt{8.993} \approx 3\].Thus, the electron is in the state \( n = 3 \).
03

Relating Angular Momentum to Quantum Number n

In the Bohr model, the angular momentum \( L \) of an electron is quantized and given by:\[ L = n\hbar \]where \( \hbar = \frac{h}{2\pi} \) is the reduced Planck’s constant, with \( h = 6.626 \times 10^{-34} \text{Js} \).
04

Calculate the Angular Momentum

Substitute \( n = 3 \) into the angular momentum formula:\[ L = 3\hbar = 3 \times \frac{6.626 \times 10^{-34}}{2\pi} \text{ J s} \]\[ L \approx 3 \times 1.055 \times 10^{-34} \text{ J s} \]\[ L \approx 3.165 \times 10^{-34} \text{ J s} \].

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Angular Momentum in the Bohr Model
In the Bohr model of the atom, the concept of angular momentum is key to understanding how electrons move around the nucleus. Angular momentum, often represented as \( L \), describes the quantity of motion an object has when it is rotating. In the context of electrons in atoms, it refers to how much motion the electron has as it orbits the nucleus.

  • The angular momentum in Bohr's model is quantized, meaning it can only take certain discrete values.
  • This quantization means that electrons can only orbit the nucleus in specific, allowable paths or energy levels.
  • The formula for the angular momentum in the Bohr model is \( L = n\hbar \), where \( n \) is the principal quantum number and \( \hbar \) is the reduced Planck's constant.
This concept of quantized angular momentum was revolutionary because it explained why electrons do not spiral into the nucleus but instead remain stable in certain orbits. Each orbit corresponds to a specific energy level, as determined by the principal quantum number \( n \).
Hydrogen Atom and Its Unique Simplicity
The hydrogen atom holds a special place in atomic physics because it is the simplest atom, consisting of just one proton and one electron. This simplicity makes it an ideal candidate for studying atomic structure and led to the development of the Bohr model.

  • In the Bohr model, the hydrogen atom's electron orbits the nucleus at certain fixed distances, corresponding to specific energy levels.
  • These distinct energy levels are why hydrogen's emission spectrum shows discrete lines, each representing a photon emitted when the electron jumps between levels.
  • This quantized model successfully explained many observations, such as the Balmer series in the hydrogen emission spectrum.
The Bohr model, although a simplification, provided a foundation for further quantum mechanics, demonstrating how discrete energy levels lead to the unique behavior of electrons in atoms. It is particularly relevant when discussing angular momentum quantization and the roles these concepts play in atomic theory.
Principal Quantum Number and Energy Levels
The principal quantum number, denoted as \( n \), is one of the four quantum numbers used to describe the unique quantum state of an electron. In the Bohr model, \( n \) describes the energy level or shell that an electron occupies around the nucleus.

  • Each value of \( n \) corresponds to a different energy level, with \( n = 1 \) being the closest to the nucleus and lower in energy.
  • As \( n \) increases, the energy level becomes higher and the electron's average distance from the nucleus increases.
  • The energy of an electron in a hydrogen atom is given by the formula \( E_n = -\frac{13.6 \, \text{eV}}{n^2} \), showing that energy levels are inversely proportional to the square of \( n \).
This quantization of energy levels is fundamental in understanding how electrons behave in atoms. For example, when an electron moves to a higher energy level (higher \( n \)), it must absorb energy, and when it drops to a lower level (lower \( n \)), it releases energy in the form of light. The concept of \( n \) is not only vital for hydrogen's atomic structure but also plays a crucial role in predicting the possible states and transitions of electrons in multi-electron atoms.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A 4.78 -MeV alpha particle from a \(^{226} \mathrm{Ra}\) decay makes a head-on collision with a uranium nucleus. A uranium nucleus has 92 protons. (a) What is the distance of closest approach of the alpha particle to the center of the nucleus? Assume that the uranium nucleus remains at rest and that the distance of closest approach is much greater than the radius of the uranium nucleus. (b) What is the force on the alpha particle at the instant when it is at the distance of closest approach?

In a TV picture tube the accelerating voltage is 15.0 \(\mathrm{kV}\) , and the electron beam passes through an aperture 0.50 \(\mathrm{mm}\) in diameter to a screen 0.300 \(\mathrm{m}\) away. (a) Calculate the uncertainty in the component of the electron's velocity perpendicular to the line between aperture and screen. (b) What is the uncertainty in position of the point where the electrons strike the screen? (c) Does this uncertainty affect the clarity of the picture significantly? (Use nonrelativistic expressions for the motion of the electrons. This is fairly accurate and is certainly adequate for obtaining an estimate of uncertainty effects.)

(a) Using the Bohr model, calculate the speed of the electron in a hydrogen atom in the \(n=1,2,\) and 3 levels. (b) Calculate the orbital period in each of these levels. (c) The average lifetime of the first excited level of a hydrogen atom is \(1.0 \times 10^{-8}\) s. In the Bohr model, how many orbits does an electron in the \(n=2\) level complete before returning to the ground level?

(a) What is the smallest amount of energy in electron volts that must be given to a hydrogen atom initially in its ground level so that it can emit the \(H_{\alpha}\) line in the Balmer series? (b) How many different possibilities of spectral-line emissions are there for this atom when the electron starts in the \(n=3\) level and eventually ends up in the ground level? Calculate the wavelength of the emitted photon in each case.

A hydrogen atom initially in the ground level absorbs a photon, which excites it to the \(n=4\) level. Determine the wavelength and frequency of the photon.

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.