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A sinusoidal electromagnetic wave is propagating in vacuum in the \(+ z\) -direction. If at a particular instant and at a certain point in space the electric field is in the \(+ x - x -\) -direction and has mag- nitude \(4.00 \mathrm { V } / \mathrm { m } ,\) what are the magnitude and direction of the magnetic field of the wave at this same point in space and instant in time?

Short Answer

Expert verified
The magnetic field has a magnitude of \(1.33 \times 10^{-8} \text{ T} \) and is in the "+y" direction.

Step by step solution

01

Understand the Relationship Between Electric and Magnetic Fields

In a sinusoidal electromagnetic wave propagating in vacuum, the electric field (E) and magnetic field (B) are perpendicular to each other and to the direction of propagation. Given the electric field is in the "+x" or "-x" direction, and the wave is moving in the "+z" direction, the magnetic field (B) must be in the "y" direction, either "+y" or "-y", to complete the right-handed coordinate system.
02

Use the Equation Relating E and B in a Vacuum

The equation relating the magnitudes of electric field (E) and magnetic field (B) in a vacuum is: \[ c = \frac{E}{B} \] where \( c \) is the speed of light \( (3.00 \times 10^8 \text{ m/s}) \). Rearrange this to solve for B: \[ B = \frac{E}{c} \]
03

Substitute the Values into the Equation

Plug the given value of the electric field into the equation: \[ B = \frac{4.00 \text{ V/m}}{3.00 \times 10^8 \text{ m/s}} \]
04

Calculate the Magnitude of the Magnetic Field

Perform the division to find the magnitude of B: \[ B = \frac{4.00}{3.00 \times 10^8} = 1.33 \times 10^{-8} \text{ T} \]
05

Determine the Direction of the Magnetic Field

Since the electric field is in the "+x" or "-x" direction and the wave is propagating in the "+z" direction, apply the right-hand rule. Curl the fingers of your right hand from the electric field direction to the propagation direction; your thumb points in the direction of the magnetic field, which is "+y" or "-y". Here, the initial indication is "+x", so B is in the "+y" direction.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Electric Field
The electric field is a fundamental concept in electromagnetism. It describes the force that a charged particle experiences in space. In an electromagnetic wave, the electric field oscillates perpendicular to the direction of wave propagation. This means if a wave moves in the +z direction, as in the given exercise, the electric field can be directed along the x-axis (or -x-axis).

To visualize it, imagine holding a pencil representing the propagation direction. If you extend your fingers perpendicular to the pencil, that's the direction the electric field might point. The electric field's magnitude tells us the strength of this push or pull a charged particle would feel. In this exercise, the electric field has a magnitude of 4.00 V/m. This indicates the potential energy difference that exists per unit charge in that field.

Keep in mind, the electric field and magnetic field together form the electromagnetic wave, and they are always at right angles to each other and to their direction of motion.
Magnetic Field
The magnetic field is another crucial component of electromagnetic waves. Alongside the electric field, it helps in transferring the energy in these waves. In a traveling electromagnetic wave, the magnetic field oscillates perpendicular to the electric field and the direction of the wave's travel.

From the exercise, the electromagnetic wave is moving along the +z axis, and the electric field is in the +x direction. The magnetic field (B) must, therefore, be in the y-direction to maintain perpendicularity and agree with the right-handed coordinate system. The relation of B with E is governed by the speed of light, given by the formula:
  • \[ c = \frac{E}{B} \]
Rearranging this allows us to find B:
  • \[ B = \frac{E}{c} \]
When we plug in the values, B becomes approximately 1.33 x 10^(-8) T, indicating a rather small but significant component of the wave.
Right-Handed Coordinate System
The right-handed coordinate system is a helpful method to determine directions in a three-dimensional space, especially when dealing with vectors. It is called so because it uses the orientation of your right hand to deduce directions. For electromagnetic waves, this system is imperative for finding the magnetic field direction when the electric field and the direction of wave propagation are known.

If you curl the fingers of your right hand from the positive x direction (where the electric field is in the exercise) to the positive z direction (the direction of wave propagation), your thumb will point in the direction of the positive y-axis where the magnetic field exists. This right-hand rule ensures consistency and allows us to visualize how the fields relate without error. This is why the magnetic field is concluded to be in either the +y or -y direction, fitting snuggly into this spatial orientation.
Speed of Light
The speed of light is a universal constant (denoted as \(c\)), and it plays a crucial role in the nature of electromagnetic waves. Light travels in a vacuum at approximately 3.00 x 10^8 m/s, a speed that ties together the electric and magnetic fields in these waves.

In the context of this exercise, understanding the speed of light helps in calculating the magnetic field's magnitude. As mentioned earlier, the relationship between the electric field (E) and the magnetic field (B) is given by:
  • \[ c = \frac{E}{B} \]
This equation shows the direct proportionality of E and B with light's speed, illustrating how tightly they are interlinked. Faster or slower speeds of these fields wouldn't comply with the rigid framework of electromagnetism defined by the speed of light, highlighting its essential role in consistently determining the behavior of electromagnetic waves.

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Most popular questions from this chapter

An electromagnetic standing wave in air has frequency 75.0\(\mathrm { MHz }\) . (a) What is the distance between nodal planes of the \(\vec { \boldsymbol { E } }\) field? (b) What is the distance between a nodal plane of \(\vec { \boldsymbol { E } }\) and the closest nodal plane of \(\vec { \boldsymbol { B } }\) ?

High-Energy Cancer Treatment. Scientists are working on a new technique to kill cancer cells by zapping them with ultrahigh-energy (in the range of \(10 ^ { 12 } \mathrm { W } )\) pulses of light that last for an extremely short time (a few nanoseconds). These short pulses scramble the interior of a cell without causing it to explode, as long pulses would do. We can model a typical such cell as a disk 5.0\(\mu \mathrm { m }\) in diameter, with the pulse lasting for 4.0\(\mathrm { ns }\) with an average power of \(2.0 \times 10 ^ { 12 } \mathrm { W }\) . We shall assume that the energy is spread uniformly over the faces of 100 cells for each pulse. (a) How much energy is given to the cell during this pulse? (b) What is the intensity (in \(\mathrm { W } / \mathrm { m } ^ { 2 }\) ) delivered to the cell? (c) What are the maximum values of the electric and magnetic fields in the pulse?

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A circular loop of wire has radius 7.50\(\mathrm { cm } .\) A sinusoidal electromagnetic plane wave trave traveling in air passes through the loop, with the direction of the magnetic field of the wave perpendicular to the plane of the loop. The intensity of the wave at the location of the loop is \(0.0195 \mathrm { W } / \mathrm { m } ^ { 2 } ,\) and the wavelength of the wave is 6.90\(\mathrm { m } .\) What is the maximum emf induced in the loop?

For a sinusoidal electromagnetic wave in vacuum, such as that described by Eq. (32.16), show that the average energy density in the electric field is the same as that in the magnetic field.

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