/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 28 In the 25 -ft Space Simulator fa... [FREE SOLUTION] | 91影视

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In the 25 -ft Space Simulator facility at NASA's Jet Propulsion Laboratory, a bank of overhead are lamps can produce light of intensity 2500\(\mathrm { W } / \mathrm { m } ^ { 2 }\) at the floor of the facility. This simulates the intensity of sunlight near the planet Venus.) Find the average radiation pressure (in pascals and in atmospheres) on (a) a totally absorbing section of the floor and (b) a totally reflection section of the floor. (c) Find the average momentum densit (momentum per unit volume) in the light at the floor.

Short Answer

Expert verified
(a) 8.33 脳 10鈦烩伓 Pa (8.22 脳 10鈦宦孤 atm); (b) 1.67 脳 10鈦烩伒 Pa (1.65 脳 10鈦宦光伆 atm); (c) 2.78 脳 10鈦宦光伌 kg/m鲁

Step by step solution

01

Understanding Radiation Pressure Formula

Radiation pressure (P) on a surface due to light is calculated differently based on whether the surface is absorbing or reflecting. For a totally absorbing surface, the formula is:\[ P = \frac{I}{c} \]For a totally reflecting surface, the formula is:\[ P = \frac{2I}{c} \]where \( I \) is the intensity of the light and \( c \) is the speed of light in vacuum (\( c = 3 \times 10^8 \) m/s).
02

Calculating Radiation Pressure on Absorbing Surface

Using the formula for an absorbing surface, the radiation pressure is:\[ P_{\text{absorb}} = \frac{I}{c} = \frac{2500 \ \mathrm{W/m^2}}{3 \times 10^8 \ \mathrm{m/s}} \]Calculating this gives:\[ P_{\text{absorb}} \approx 8.33 \times 10^{-6} \ \mathrm{Pa} \]
03

Calculating Radiation Pressure on Reflecting Surface

Using the formula for a reflecting surface, the radiation pressure is:\[ P_{\text{reflect}} = \frac{2I}{c} = \frac{2 \times 2500 \ \mathrm{W/m^2}}{3 \times 10^8 \ \mathrm{m/s}} \]Calculating this gives:\[ P_{\text{reflect}} \approx 1.67 \times 10^{-5} \ \mathrm{Pa} \]
04

Converting Pressure from Pascals to Atmospheres

To convert from pascals to atmospheres, we use the conversion: 1 atm = 101325 Pa.For the totally absorbing surface:\[ P_{\text{absorb (atm)}} = \frac{8.33 \times 10^{-6} \ \mathrm{Pa}}{101325 \ \mathrm{Pa/atm}} \approx 8.22 \times 10^{-11} \ \mathrm{atm} \]For the totally reflecting surface:\[ P_{\text{reflect (atm)}} = \frac{1.67 \times 10^{-5} \ \mathrm{Pa}}{101325 \ \mathrm{Pa/atm}} \approx 1.65 \times 10^{-10} \ \mathrm{atm} \]
05

Calculating Average Momentum Density

The average momentum density \( u \) in light can be calculated using the formula related to light intensity and speed:\[ u = \frac{I}{c^2} \]Substituting the given values:\[ u = \frac{2500 \ \mathrm{W/m^2}}{(3 \times 10^8 \ \mathrm{m/s})^2} \]\[ u \approx 2.78 \times 10^{-14} \ \mathrm{kg/m^3} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Radiation Pressure Formula
Radiation pressure is the pressure exerted by electromagnetic radiation on any surface it strikes. This force arises because light carries momentum as it travels. The pressure exerted differs depending on whether the surface fully absorbs or reflects the light.

For a totally absorbing surface, the formula to calculate radiation pressure is given by:
  • \( P = \frac{I}{c} \), where \( P \) is the radiation pressure, \( I \) is the intensity of the light, and \( c \) is the speed of light in vacuum (approximately \( 3 \times 10^8 \) m/s).
On the other hand, for a totally reflecting surface, the formula is:
  • \( P = \frac{2I}{c} \). This formula accounts for the fact that the momentum change is double compared to an absorbing surface, due to the light being reflected back.
This distinction is crucial when understanding how different types of surfaces interact with light, influencing calculations in contexts like space travel and energy technologies.
Totally Absorbing Surface
A totally absorbing surface, as the name suggests, completely absorbs all the incident light. None of the light is reflected back into the environment.

In practical applications, this is important as:
  • Such surfaces are used in various scientific instruments to prevent unwanted reflections.
  • For computations, the absorbed energy transforms entirely into thermal or other forms, depending on the material properties.
When calculating radiation pressure on a totally absorbing surface, use the formula \( P = \frac{I}{c} \). For example, with a light intensity \( I = 2500 \ \mathrm{W/m^2} \), the radiation pressure is about \( 8.33 \times 10^{-6} \ \mathrm{Pa} \). Converting this to atmospheres (where \( 1 \ \mathrm{atm} = 101325 \ \mathrm{Pa} \)), we get approximately \( 8.22 \times 10^{-11} \ \mathrm{atm} \).

This showcases the minute yet significant effect of radiation pressure in fields like astrobiology and satellite technology.
Momentum Density
Momentum density of light is a less intuitive concept than radiation pressure, but just as important. It refers to the momentum carried by the light per unit volume.

The formula for calculating momentum density \( u \) is:
  • \( u = \frac{I}{c^2} \)
where \( u \) is the momentum density, \( I \) is the intensity of light, and \( c^2 \) is the square of the speed of light.

In our example, given \( I = 2500 \ \mathrm{W/m^2} \) and using the speed of light \( c = 3 \times 10^8 \ \mathrm{m/s} \), the momentum density calculates to approximately \( 2.78 \times 10^{-14} \ \mathrm{kg/m^3} \).

This measurement helps in understanding the energy transport properties of light, crucial in fields such as photonics and laser technology.
Intensity of Sunlight
Intensity of sunlight refers to the amount of solar power received per unit area. It is a fundamental parameter in solar energy applications and is mostly measured in watts per square meter (\( W/m^2 \)).

At NASA's Jet Propulsion Laboratory, simulating the sunlight intensity for planetary studies is critical. For instance, in the exercise, the intensity of 2500 \( \mathrm{W/m^2} \) is used to mimic the conditions near Venus. This high intensity is typical for environments closer to the sun, helping scientists simulate and study conditions as accurately as possible.

Understanding sunlight intensity allows engineers to improve solar panel efficiency and design, cater to climate models, and plan for long-duration space missions where solar energy is a critical resource.

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Most popular questions from this chapter

Consider electromagnetic waves propagating in air. (a) Determine the frequency of a wave with a wavelength of (i) 5.0\(\mathrm { km }\) , (ii) \(5.0 \mu \mathrm { m } ,\) (iii) 5.0\(\mathrm { nm }\) . (b) What is the wavelength (in meters and nanometers) of (i) gamma rays of frequency \(6.50 \times 10 ^ { 21 } \mathrm { Hz }\) and (ii) an AM station radio wave of frequency 590\(\mathrm { kHz }\) ?

Radio station WCCO in Minneapolis broadcasts at a frequency of 830\(\mathrm { kHz }\) . At a point some distance from the transmitter, the magnetic-field amplitude of the electromagnetic wave from WCCO is \(4.82 \times 10 ^ { - 111 } \mathrm { T.Calculate }\) (a) the wavelength; (b) the wave number; (c) the angular frequency; (d) the electric-field amplitude.

An electromagnetic wave with frequency 65.0 Hz travels in an insulating magnetic material that has dielectric constant 3.64 and relative permeability 5.18 at this frequency. The electric field has amplitude \(7.20 \times 10 ^ { - 3 } \mathrm { V } / \mathrm { m }\) . (a) What is the speed of propagation of the wave? (b) What is the wavelength of the wave? (c) What is the amplitude of the magnetic field?

You want to support a sheet of fireproof paper horizon tally, using only a vertical upward beam of light spread uniformly over the sheet. There is no other light on this paper. The sheet measures 22.0\(\mathrm { cm }\) by 28.0\(\mathrm { cm }\) and has a mass of 1.50\(\mathrm { g }\) . (a) If the paper is black and hence absorbs all the light that hits it, what must be the intensity of the light beam? (b) For the light in part (a), what are the amplitudes of its electric and magnetic fields? (c) If the paper is white and hence reflects all the light that hits it, what intensity of light beam is needed to support it? (d) To see if it is physically reasonable to expect to support a sheet of paper this way, calculate the intensity in a typical 0.500 -mW laser beam that is 1.00\(\mathrm { mm }\) in diameter, and compare this value with your answer in part (a).

A cylindrical conductor with a circular cross section has a radius \(a\) and a resistivity \(\rho\) and carries a constant current \(I\) (a) What are the magnitude and direction of the electric-field vector \(E\) at a point just inside the wire at a distance \(a\) from the axis? (b) What are the magnitude and direction of the magneticfield vector \(\vec { \boldsymbol { B } }\) at the same point? \(( \mathrm { c } )\) What are the magnitude and direction of the Poynting vector \(\vec { \boldsymbol { S } }\) at the same point? (The direction of \(\vec { \boldsymbol { S } }\) is the direction in which electromagnetic energy flows into or out of the conductor.) (d) Use the result in part (c) to find the rate of flow of energy into the volume occupied by a length \(l\) of the conductor. (Hint: Integrate \(\vec { S }\) over the surface of this volume.) Compare your result to the rate of generation of thermal energy in the same volume. Discuss why the energy dissipated in a current carrying conductor, due to its resistance, can be thought of as entering through the cylindrical sides of the conductor.

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