/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 30 At its Ames Research Center, NAS... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

At its Ames Research Center, NASA uses its large "20-G" centrifuge to test the effects of very large accelerations ("hypergravity") on test pilots and astronauts. In this device, an arm 8.84 m long rotates about one end in a horizontal plane, and the astronaut is strapped in at the other end. Suppose that he is aligned along the arm with his head at the outermost end. The maximum sustained acceleration to which humans are subjected in this machine is typically 12.5\(g\) . (a) How fast must the astronaut's head be moving to experience this maximum acceleration? (b) What is the difference between the acceleration of his head and feet if the astronaut is 2.00 \(\mathrm{m}\) tall? (c) How fast in rpm (rev/min) is the arm turning to produce the maximum sustained acceleration?

Short Answer

Expert verified
(a) 33.0 m/s (b) 36.675 m/s² (c) 35.7 rpm

Step by step solution

01

Understand the Concept

The centripetal acceleration for circular motion is given by \( a = \frac{v^2}{r} \), where \( v \) is the linear velocity and \( r \) is the radius of the circular path. We are given \( a = 12.5g \) and need the velocity \( v \) of the astronaut's head.
02

Calculate Velocity for Maximum Acceleration

Set \( a = 12.5g = 12.5 \times 9.81 \, \text{m/s}^2 \) and rearrange the formula to solve for \( v \): \( v = \sqrt{a \times r} \). Substitute \( r = 8.84 \, \text{m} \) into the formula to find \( v \).
03

Calculation for Velocity

Substitute and solve: \( v = \sqrt{12.5 \times 9.81 \times 8.84} \approx 33.0 \text{ m/s} \). This is the speed required for the astronaut's head.
04

Determine Difference Between Head and Feet Acceleration

The astronaut's head is at \( r = 8.84 \, \text{m} \) and feet are at \( r = 8.84 \, \text{m} - 2.0 \, \text{m} = 6.84 \, \text{m} \). Calculate acceleration of the feet using \( a = \frac{v^2}{r} \).
05

Calculate Feet's Acceleration

Use \( v = 33.0 \, \text{m/s} \) and \( r = 6.84 \, \text{m} \): \( a_{feet} = \frac{33.0^2}{6.84} \approx 159.3 \, \text{m/s}^2 \). The head acceleration is \( 12.5g \approx 122.625 \, \text{m/s}^2 \). Difference is \( 159.3 - 122.625 \approx 36.675 \, \text{m/s}^2 \).
06

Convert Linear Speed to Angular Speed

Convert the linear speed \( v \) to angular speed \( \omega \) using \( \omega = \frac{v}{r} \). Then, convert \( \omega \) from rad/s to rpm by multiplying by \( \frac{60}{2\pi} \).
07

Calculate Angular Speed in RPM

Determine \( \omega = \frac{33.0}{8.84} \approx 3.73 \, \text{rad/s} \). Convert \( \omega \) to rpm: \( \text{rpm} = 3.73 \times \frac{60}{2\pi} \approx 35.7 \text{ rpm} \).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Circular Motion
Circular motion occurs when an object travels in a path at a constant distance from a central point. This path, known as a circular path, can be observed in many natural and technological processes, from the orbit of planets to amusement park rides. When an object is in circular motion, its velocity is continuously changing direction, even if its speed is constant. This change in direction results in what we call centripetal acceleration, which always acts towards the center of the circle. The formula for centripetal acceleration is \( a = \frac{v^2}{r} \), where \( v \) is the linear velocity and \( r \) is the radius of the circle.
In the case of the NASA centrifuge, the astronaut experiences circular motion as they're rotated at the end of an 8.84-meter arm. The inquisitive motion controlled by the centrifuge creates a substantial inward centripetal force to simulate high gravity conditions. Understanding circular motion is essential to solving many practical problems and helps engineers design safe, effective equipment.
Linear Velocity
Linear velocity describes the speed and direction of an object moving along a straight or curved path. In circular motion, linear velocity refers to how fast an object travels along the circular path, created by the radius of rotation. The linear velocity \( v \) at any point in circular motion should not be confused with the angular speed, because it represents a different physical quantity. Linear velocity is a vector, thus it considers both magnitude (speed) and direction.
For example, in the 20-G centrifuge at NASA, the astronaut's head experiences a specific linear velocity computed to achieve a desired centripetal acceleration. Knowing this linear velocity (calculated as approximately 33.0 m/s) helps scientists understand how the body may react under intense forces. When working with physics problems, always keep in mind that linear velocity is proportional to the radius of the circle and the angular speed.
Angular Speed
Angular speed is a measure of how quickly an object rotates around an axis. It is expressed in terms of radians per second (rad/s) and represents how much of the angle is covered per unit of time. In the context of circular motion, angular speed is often converted to revolutions per minute (rpm) for easier interpretation.
  • Formula: \( \omega = \frac{v}{r} \)
  • Conversion: \( \text{rpm} = \omega \times \frac{60}{2\pi} \)
Angular speed is an essential concept not only in understanding circular motion but also in practical scenarios, such as designing machinery or conducting scientific experiments. For NASA’s centrifuge challenge, the angular speed determines how fast the arm rotates to achieve the necessary linear velocity and acceleration experienced by the astronaut. Conversion into rpm helps bridge the understanding between abstract physics and real-world measurements.
NASA Research
NASA research encompasses a wide range of scientific and technological endeavors, including innovations in space exploration, aeronautics, and technology development. A key component of NASA’s research is understanding how extreme conditions affect human physiology, especially concerning astronauts.
This is where centrifuge testing plays an important role. By simulating hypergravity conditions using centrifuges, NASA researchers can study the limits of human endurance and better prepare astronauts for the challenges they may face in space. These studies not only influence space mission design but also contribute to medical and physiological knowledge that benefits medical science.
  • Focus on space travel readiness
  • Effects of gravity extremes
  • Advancements in technology
By addressing these areas, NASA continues to lead in both exploratory missions and valuable scientific contributions on Earth.
Centrifuge Testing
Centrifuge testing is a crucial method used by researchers to study the effects of different gravity levels on human subjects or equipment. In these tests, objects or people are placed at the end of a rotating arm, simulating gravitational forces much higher than those typically experienced on Earth.
In the case of NASA's Ames Research Center, the 20-G centrifuge is used to simulate hypergravity conditions, providing valuable data on how the human body responds to extended periods of high G-force. These tests are key to ensuring the safety and performance of astronauts in conditions of rapid acceleration and deceleration.
  • Simulates high-gravity environments
  • Examines physiological responses
  • Helps in designing safer space missions
The knowledge gained from centrifuge testing is vital for developing equipment and training protocols that keep astronauts safe during spaceflight. Additionally, it has applications in building vehicles and protective gear that withstand high stresses in varied environments.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A rookie quarterback throws a football with an initial upward velocity component of 12.0 \(\mathrm{m} / \mathrm{s}\) and a horizontal velocity component of 20.0 \(\mathrm{m} / \mathrm{s} .\) Ignore air resistance. (a) How much time is required for the football to reach the highest point of the trajectory? (b) How high is this point? (c) How much time (after it is thrown) is required for the football to return to its original level? How does this compare with the time calculated in part (a)? (d) How far has the football traveled horizontally during this time? (e) Draw \(x-t, y-t, v_{x^{-}} t,\) and \(v_{y}-t\) graphs for the motion.

In a World Cup soccer match, Juan is running due north toward the goal with a speed of 8.00 \(\mathrm{m} / \mathrm{s}\) relative to the ground. A teammate passes the ball to him. The ball has a speed of 12.0 \(\mathrm{m} / \mathrm{s}\) and is moving in a direction \(37.0^{\circ}\) east of north, relative to the ground. What are the magnitude and direction of the ball's velocity relative to Juan?

A car traveling on a level horizontal road comes to a bridge during a storm and finds the bridge washed out. The driver must get to the other side, so he decides to try leaping it with his car. The side of the road the car is on is 21.3 \(\mathrm{m}\) above the river, while the opposite side is a mere 1.8 \(\mathrm{m}\) above the river. The river itself is a raging torrent 61.0 \(\mathrm{m}\) wide. (a) How fast should the car be traveling at the time it leaves the road in order just to clear the river and land safely on the opposite side? (b) What is the speed of the car just before it lands on the other side?

When a train's velocity is 12.0 \(\mathrm{m} / \mathrm{s}\) eastward, raindrops that are falling vertically with respect to the earth make traces that are inclined \(30.0^{\circ}\) to the vertical on the windows of the train. (a) What is the horizontal component of a drop's velocity with respect to the earth? With respect to the train? (b) What is the magnitude of the velocity of the raindrop with respect to the earth? With respect to the train?

Tossing Your Lunch. Henrietta is going off to her physics class, jogging down the sidewalk at 3.05 \(\mathrm{m} / \mathrm{s} .\) Her husband Bruce suddenly realizes that she left in such a hurry that she forgot her lunch of bagels, so he runs to the window of their apartment, which is 38.0 \(\mathrm{m}\) above the street level and directly above the sidewalk, to throw them to her. Bruce throws them horizontally 9.00 s after Henrietta has passed below the window, and she catches them on the run. You can ignore air resistance. (a) With what initial speed must Bruce throw the bagels so Henrietta can catch them just before they hit the ground? (b) Where is Henrietta when she catches the bagels?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.