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When a train's velocity is 12.0 \(\mathrm{m} / \mathrm{s}\) eastward, raindrops that are falling vertically with respect to the earth make traces that are inclined \(30.0^{\circ}\) to the vertical on the windows of the train. (a) What is the horizontal component of a drop's velocity with respect to the earth? With respect to the train? (b) What is the magnitude of the velocity of the raindrop with respect to the earth? With respect to the train?

Short Answer

Expert verified
The horizontal component of the drop's velocity with respect to the earth is 12 m/s, and with respect to the train is 0 m/s. The magnitude of the raindrop's velocity with respect to the earth is also the same as the vertical component, while with respect to the train it is approximately \(v_{vertical} \times \sqrt{2} \).

Step by step solution

01

Understand the Problem

We have a train moving eastward at 12.0 m/s and raindrops falling vertically with respect to the earth. On the train's windows, the raindrops make a 30° angle with the vertical. We need to find the horizontal components of the raindrop's velocity with respect to both the earth and the train, and finally the magnitude of the raindrop's velocity with respect to both.
02

Set Up the Trigonometric Relationship

The angle given is 30° from the vertical. The velocity of the raindrop forms a right triangle with this angle. The vertical component is along the hypotenuse, and the horizontal component forms the base of this triangle. Use the trigonometric identity: \( \tan(\theta) = \frac{{ ext{horizontal component}}}{ ext{vertical component}} \).
03

Calculate Horizontal Component with Respect to Earth

Since the raindrop is falling vertically with respect to the earth, its vertical component is its only component in this frame. With the angle \( \theta = 30° \), the horizontal component (base of the triangle) with respect to the train is: \( \tan(30°) = \frac{v_{train}}{v_{vertical}} \), where \( v_{train} = 12.0 \text{ m/s} \). Rearrange to find the horizontal component: \( v_{vertical} = v_{train} \times \sqrt{3} \approx 12 \text{ m/s} \times \sqrt{3} \). Solve for the horizontal component.
04

Compute Horizontal Component with Respect to the Train

With respect to the train, the horizontal component of the raindrop's velocity is simply the horizontal component with respect to the earth minus the velocity of the train: \( v_{h, train} = v_{horizontal} - 12.0 \text{ m/s} \).
05

Find Velocity Magnitude with Respect to Earth

The velocity of the drop with respect to the earth includes only the vertical component \( v_{vertical} \), as calculated from Step 3. This is because with respect to the earth, the drop only has a vertical motion.
06

Determine Magnitude of Velocity with Respect to the Train

Using Pythagoras' theorem in the triangle, the magnitude of the raindrop's velocity with respect to the train is found by combining both horizontal and vertical components: \( v_{total} = \sqrt{v_{h, train}^2 + v_{vertical}^2} \). Substitute the known values to calculate.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Trigonometry in Physics
Trigonometry in physics helps us understand the relationships between different components of motion. In this exercise, we see how trigonometry is crucial when analyzing the motion of raindrops relative to both the earth and a moving train. When we speak of a right triangle in physics, each side usually represents a different component of velocity or force.
One side might represent the vertical component, while another represents the horizontal component. The angle given helps us determine the relationship between these components. Here, the angle between the raindrop traces and the vertical revealed a trigonometric identity: the tangent function.
This identity is expressed as:
  • \( \tan(\theta) = \frac{\text{horizontal component}}{\text{vertical component}} \)
With this expression, the motion's intricacies become clearer. The tangent of the angle reveals how the raindrop's horizontal motion is related to its vertical fall with respect to the observer, i.e., the moving train. By applying this trigonometric relationship, we unveil a more comprehensive understanding of the nature of raindrop motion relative to different frames of reference.
Kinematics
Kinematics is the branch of physics that studies the motion of objects without considering the causes behind them. It’s a cornerstone of understanding how various forces act in projectile motion and relative velocity scenarios.
In this exercise, we explored how to analyze velocity components in different reference frames. The train’s eastward speed of 12.0 m/s influenced our understanding of the relative motion of the raindrops.
We can compute the horizontal component of the raindrop's velocity with respect to the Earth. Since the train moves eastward and the raindrop appears to have an eastward velocity due to this motion, kinematics allows us to decouple these components:
  • The horizontal velocity with respect to the Earth was affected by the train’s speed.
  • Using the tangent function, we derived the horizontal component of motion that needed to sync with both train and Earth frames.
When considering motion from the train's point of view, we subtract the train's velocity from the raindrop's relative horizontal motion. This showcases kinematics' importance in breaking down and solving motion problems in different frames of reference.
Projectile Motion
Projectile motion involves analyzing the path of an object that moves in different directions under the influence of gravity alone.
In this scenario, the raindrops behave like tiny projectiles. Despite falling vertically with respect to the ground, the horizontal motion is induced relative to the moving train. How the raindrop's path appears is influenced greatly by the observer's frame of reference. In the two frames – Earth vs the moving train – the perceived motion differs.
Using Pythagorean theorem, the combination of horizontal and vertical velocity components leads us to discover the resultant velocity of the raindrop with respect to the train:
  • \( v_{total} = \sqrt{v_{horizontal}^2 + v_{vertical}^2} \)
This combined velocity shows that raindrops, though falling vertically with respect to Earth, appear to trace for the observer on the train a path inclined to the vertical.
Projectile motion concepts are everywhere – from raindrops on a train window to thrown baseballs. Breaking down the components helps students understand how they can predict and describe such paths in the physical world.

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Most popular questions from this chapter

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