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Cp Antenna emf. A satellite, orbiting the earth at the equator at an altitude of \(400 \mathrm{km},\) has an antenna that can be modeled as a 2.0 -m-long rod. The antenna is oriented perpendicular to the earth's surface. At the equator, the earth's magnetic field is essentially horizontal and has a value of \(8.0 \times 10^{-5} \mathrm{T}\) ; ignore any changes in \(B\) with altitude. Assuming the orbit is circular, determine the induced emf between the tips of the antenna.

Short Answer

Expert verified
The induced emf across the antenna is calculated using Faraday's law, considering the satellite's velocity and the given magnetic field.

Step by step solution

01

Understand the Formula for Emf

The formula to calculate the induced emf in a moving conductor (the antenna in this case) is given by Faraday's Law of Induction as \( \epsilon = B \cdot v \cdot L \cdot \sin(\theta) \), where \( \epsilon \) is the emf, \( B \) is the magnetic field strength, \( v \) is the velocity of the antenna, \( L \) is the length of the antenna, and \( \theta \) is the angle between the magnetic field and the velocity of the antenna. Since the magnetic field is horizontal and the antenna is perpendicular to it, \( \theta = 90^\circ \) and thus \( \sin(\theta) = 1 \).
02

Calculate the Velocity of the Satellite

To find the velocity \( v \) of the satellite, use the formula for circular orbital velocity: \( v = \sqrt{\frac{GM}{R}} \), where \( G \) is the gravitational constant \( 6.674 \times 10^{-11} \mathrm{Nm}^2/\mathrm{kg}^2 \), \( M \) is the mass of the Earth \( 5.972 \times 10^{24} \mathrm{kg} \), and \( R \) is the distance from the center of Earth to the satellite, which is the Earth's radius \( 6.371 \times 10^{6} \mathrm{m} \) plus the altitude \( 400 \times 10^{3} \mathrm{m} \). Calculate \( R \) and then \( v \).
03

Substitute Values into the Emf Formula

Now, substitute the values into the emf formula: \( B = 8.0 \times 10^{-5} \mathrm{T} \), the calculated \( v \), and \( L = 2.0 \mathrm{m} \) into \( \epsilon = B \cdot v \cdot L \). This will give you the induced emf.
04

Final Calculation and Interpretation

Perform the final calculation to determine the induced emf. This will involve using the velocity from Step 2, and substituting it back along with the other values into the equation from Step 1 to find \( \epsilon \). The result will be in volts and represents the potential difference induced between the tips of the antenna.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Electromagnetic Induction
Electromagnetic induction is the process by which a voltage or electromotive force (emf) is generated in a conductor due to its motion in a magnetic field. This phenomenon, first explained by Michael Faraday, is central to understanding how electrical generators and transformers work. Applications include power generation and the basic operation of electric motors. In this context, our focus is on a satellite with an antenna moving through Earth's magnetic field. The movement of the antenna through the magnetic field induces an emf, calculated using Faraday's Law of Induction. Faraday's Law states that the induced emf in a closed loop is equal to the negative change in magnetic flux through the loop over time. For a straight conductor moving in a uniform magnetic field, the emf is calculated as \( \epsilon = B \cdot v \cdot L \cdot \sin(\theta) \), where \( B \) is the magnetic flux density, \( v \) is the velocity, \( L \) is the length of the conductor, and \( \theta \) is the angle between the direction of motion and the magnetic field. By understanding these parameters, we can predict and calculate the potential difference developed across moving conductive rods or antennas.
Satellite Dynamics
Satellites orbit the Earth due to a balance of gravitational forces and the inertia of their motion. This balance keeps them in continuous free fall towards the Earth, following a circular or elliptical path. Satellite dynamics study these paths, helping us understand how satellites move and stay in orbit. With the right speed and altitude, a satellite can orbit indefinitely, as gravitational pull provides the necessary centripetal force. These principles apply to our problem, where a satellite moves in a circular orbit at the equator. To maintain this orbit, its speed must correspond to the gravitational forces acting upon it. Thus, understanding satellite dynamics is crucial when calculating the induced emf, as the velocity derived using dynamics directly contributes to the emf value.
Orbital Velocity
Orbital velocity is the speed needed for a satellite to stay in orbit around the Earth without falling back to the surface. This velocity depends on the mass of the Earth and the distance from its center to the satellite. The formula for orbital velocity is derived from equating gravitational force to the centripetal force needed for circular motion: \( v = \sqrt{\frac{GM}{R}} \). Here, \( G \) is the gravitational constant, \( M \) is the mass of the Earth, and \( R \) is the distance from the Earth's center to the satellite, including Earth's radius and the altitude of the satellite. In our problem, once the orbital velocity is calculated, it is used to determine the emf generated along the satellite's antenna. Understanding how to calculate and apply orbital velocity is essential for satellite communications and navigation systems.
Magnetic Fields
Magnetic fields are invisible forces that exert influence on charged particles and magnetic materials within the field's reach. They are characterized by field lines that represent the direction of magnetic force. Earth's magnetic field is similar to that of a giant bar magnet and plays a crucial role in navigation and communication technology. In this exercise, the Earth's magnetic field is assumed to be uniform and horizontal at the equator, with a magnitude of \( 8.0 \times 10^{-5} \mathrm{T} \). The interaction of this field with the moving satellite's antenna leads to the phenomena of electromagnetic induction. The orientation of the field lines relative to the moving conductor dictates the magnitude of the induced emf. By understanding magnetic fields, we can better grasp their effects on moving conductors, such as the aforementioned antenna in orbit, highlighting the importance of magnetic interactions in everyday technology.

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Most popular questions from this chapter

A long, thin solenoid has 400 turns per meter and radius 1.10 \(\mathrm{cm} .\) The current in the solenoid is increasing at a uniform rate \(d i / d t .\) The induced electric field at a point near the center of the solenoid and 3.50 \(\mathrm{cm}\) from its axis is \(8.00 \times 10^{-6} \mathrm{V} / \mathrm{m}\) . Calculate di/dt.

A long, straight solenoid with a cross-sectional area of 8.00 \(\mathrm{cm}^{2}\) is wound with 90 turns of wire per centimeter, and the windings carry a current of 0.350 A. A second winding of 12 turns encircles the solenoid at its center. The current in the solenoid is turned off such that the magnetic field of the solenoid becomes zero in 0.0400 s. What is the average induced emf in the second winding?

In a physics laboratory experiment, a coil with 200 turns enclosing an area of 12 \(\mathrm{cm}^{2}\) is rotated in 0.040 s from a position where its plane is perpendicular to the earth's magnetic field to a position where its plane is parallel to the field. The earth's magnetic field at the lab location is \(6.0 \times 10^{-5} \mathrm{T}\) . (a) What is the total magnetic flux through the coil before it is rotated? After it is rotated? (b) What is the average emf induced in the coil?

A circular loop of wire is in a region of spatially uniform magnetic field, as shown in Fig. E29.15. The magnetic field is directed into the plane of the figure. Determine the direction (clockwise or counterclockwise) of the induced current in the loop when (a) \(B\) is increasing; (b) \(B\) is decreasing; (c) \(B\) is constant with value \(B_{0} .\) Explain your reasoning.

A circular loop of wire with a radius of 12.0 \(\mathrm{cm}\) and oriented in the horizontal \(x y-\) plane is located in a region of uniform magnetic field. A field of 1.5 T is directed along the positive \(z\) -direction, which is upward. (a) If the loop is removed from the field region in a time interval of 2.0 \(\mathrm{ms}\) , find the average emf that will be induced in the wire loop during the extraction process. (b) If the coil is viewed looking down on it from above, is the induced current in the loop clockwise or counterclockwise?

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