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CALC In a region of space, a magnetic field points in the \(+x\) -direction (toward the right). Its magnitude varies with position according to the formula \(B_{x}=B_{0}+b x,\) where \(B_{0}\) and \(b\) are positive constants, for \(x \geq 0 .\) A flat coil of area \(A\) moves with uniform speed \(v\) from right to left with the plane of its area always perpendicular to this field. (a) What is the emf induced in this coil while it is to the right of the origin? (b) As viewed from the origin, what is the direction (clockwise or counterclockwise) of the current induced in the coil? (c) If instead the coil moved from left to right, what would be the answers to parts (a) and (b)?

Short Answer

Expert verified
(a) EMF: \( bAv \), clockwise; (b) \( bAv \), counterclockwise.

Step by step solution

01

Understand Faraday's Law of Induction

Faraday's law of induction states that an electromotive force (emf) is induced in a coil when there is a change in magnetic flux through the coil. The induced emf is given by \( \mathcal{E} = - \frac{d\Phi_B}{dt} \), where \( \Phi_B \) is the magnetic flux.
02

Calculate the Magnetic Flux

The magnetic flux \( \Phi_B \) through the coil is given by the product of the magnetic field and the area of the coil, i.e., \( \Phi_B = B_x \cdot A = (B_0 + bx)\cdot A \).
03

Determine the Change in Magnetic Flux

As the coil moves with velocity \( v \) from right to left, the position \( x \) changes with time as \( x = vt \). Therefore, \( \Phi_B = (B_0 + bvt) A \).
04

Find the Induced EMF

Differentiate the magnetic flux with respect to time to get the induced emf: \( \mathcal{E} = - \frac{d}{dt}[(B_0 + bvt)A] = - (bAv) \). The negative sign indicates the direction of the induced emf according to Lenz's law, but the magnitude of the emf is \( bAv \).
05

Determine the Direction of Induced Current When Moving Right to Left

Using Lenz's Law, the direction of the induced current is such that it opposes the change in magnetic flux. Since the coil is moving from right to left, the emf induces a current that creates its own magnetic field opposing the increase of \( B_x \). Visualizing from the origin, the induced current will be clockwise.
06

Evaluate EMF and Current Direction for Reverse Motion

If the coil moves from left to right, position increases, and the change in flux is opposite in nature, yet the magnitude of emf remains \( bAv \). However, the direction of the induced current will now be counterclockwise, as observed from the origin, still opposing the change, but now in response to decreasing flux rightward.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Magnetic Flux
Magnetic flux is a measure of the magnetic field passing through a given surface, such as the area of a coil. Think of it as the number of magnetic field lines crossing that surface. Magnetic flux (\( \Phi_B \)) can be calculated using the formula:
  • \( \Phi_B = B \cdot A \cdot \cos(\theta) \)
where:
  • \( B \) is the magnetic field strength,
  • \( A \) is the area of the surface, and
  • \( \theta \) is the angle between the magnetic field and the normal to the surface.
In our scenario, the magnetic field is given by \( B_x = B_0 + bx \), and since the coil is perpendicular to the field (\( \theta = 0 \)), the cosine factor is 1, simplifying our flux equation to \( \Phi_B = (B_0 + bx) \cdot A \). By understanding magnetic flux, you can see how a changing magnetic field or a moving coil affects the flux through it.
This change in flux is crucial for inducing electromotive force in the coil.
Induced EMF
Induced electromotive force (emf) occurs when the magnetic flux linked with a coil changes over time. This phenomenon is brilliantly explained by Faraday's Law of Induction. Mathematically, it states:
  • \( \mathcal{E} = - \frac{d\Phi_B}{dt} \)
This equation indicates that the induced emf is equal to the negative rate of change of magnetic flux through the coil. The negative sign is significant, as it relates to the direction of the induced emf.
Let's look at our exercise: as the coil moves with velocity \( v \), the position \( x \) changes in time, making the flux time-dependent (\( \Phi_B = (B_0 + bvt) \cdot A \)). Differentiating this flux with respect to time provides us the induced emf:
  • \( \mathcal{E} = - (bAv) \)
Here, \( bAv \) represents the magnitude of the emf; changing motion affects flux thus inducing this emf.
Lenz's Law
Lenz's Law is a principle that gives direction to the induced emf and current resulting from Faraday's Law. Simply put, it tells us the induced emf will always work to oppose the change that produced it. Imagine you're a magnetic field 'conductor' – your goal is to resist any change in magnetic flux. In practical terms, if you move a coil through a magnetic field:
  • If the magnetic flux through the coil increases, the induced emf will generate a current that opposes this increase.
  • Conversely, if flux decreases, it will induce a current opposing this decrease.
In our problem, as the coil moves from right to left through a varying magnetic field, the direction of current induced can be found using Lenz's Law. From the origin perspective, moving right to left increases flux, so the current runs clockwise to oppose it. However, when moved from left to right, flux decreases, inducing a counterclockwise current to resist the change. Lenz's Law effectively captures nature’s inclination to resist alterations in magnetic flux.

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Most popular questions from this chapter

CALC A dielectric of permittivity \(3.5 \times 10^{-11} \mathrm{F} / \mathrm{m}\) completely fills the volume between two capacitor plates. For \(t>0\) the electric flux through the dielectric is \(\left(8.0 \times 10^{3} \mathrm{V} \cdot \mathrm{s} / \mathrm{s}^{3}\right) t^{3}\) . The dielectric is ideal and nonmagnetic; the conduction current in the dielectric is zero. At what time does the displacement current in the dielectric equal 21\(\mu \mathrm{A} ?\)

In a physics laboratory experiment, a coil with 200 turns enclosing an area of 12 \(\mathrm{cm}^{2}\) is rotated in 0.040 s from a position where its plane is perpendicular to the earth's magnetic field to a position where its plane is parallel to the field. The earth's magnetic field at the lab location is \(6.0 \times 10^{-5} \mathrm{T}\) . (a) What is the total magnetic flux through the coil before it is rotated? After it is rotated? (b) What is the average emf induced in the coil?

Back emf. A motor with a brush-and-commutator arrangement, as described in Example \(29.4,\) has a circular coil with radius 2.5 \(\mathrm{cm}\) and 150 turns of wire. The magnetic field has magnitude \(0.060 \mathrm{T},\) and the coil rotates at 440 \(\mathrm{rev} / \mathrm{min.}\) (a) What is the maximum emf induced in the coil? (b) What is the average back emf?

A long, straight solenoid with a cross-sectional area of 8.00 \(\mathrm{cm}^{2}\) is wound with 90 turns of wire per centimeter, and the windings carry a current of 0.350 A. A second winding of 12 turns encircles the solenoid at its center. The current in the solenoid is turned off such that the magnetic field of the solenoid becomes zero in 0.0400 s. What is the average induced emf in the second winding?

Terminal Speed. A conducting rod with length \(L\) mass \(m,\) and resistance \(R\) moves without friction on metal rails as shown in Fig. \(29.11 .\) A uniform magnetic field \(\vec{B}\) is directed into the plane of the figure. The rod starts from rest and is acted on by a constant force \(\vec{\boldsymbol{F}}\) directed to the right. The rails are infinitely long and have negligible resistance. (a) Graph the speed of the rod as a function of time. (b) Find an expression for the terminal speed (the speed when the acceleration of the rod is zero).

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