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Two long, parallel transmission lines, 40.0 \(\mathrm{cm}\) apart, carry \(25.0-\mathrm{A}\) and 75.0 -A currents. Find all locations where the net magnetic field of the two wires is zero if these currents are in (a) the same direction and (b) the opposite direction.

Short Answer

Expert verified
Same direction: 0.1 m; Opposite direction: 1.2 m.

Step by step solution

01

Understanding the Magnetic Field Due to a Current-Carrying Wire

The magnetic field \[ B \] at a distance \[ r \] from a long straight wire carrying a current \[ I \] is given by the formula \[ B = \frac{\mu_0 I}{2\pi r} \]. Here, \[ \mu_0 \] is the permeability of free space \( 4\pi \times 10^{-7} \ \mathrm{T \cdot m/A} \). We will use this formula to calculate the magnetic field produced by each wire at any given point.
02

Setup for Parallel Currents in the Same Direction

When the currents are in the same direction, the magnetic fields at points between the wires point in the opposite directions, causing them to oppose each other. We'll find the point where these fields cancel each other out (sum to zero). Assume the wire with \( I_a = 25.0 \ ext{A} \) is at \( x = 0 \) and the other wire with \( I_b = 75.0 \ ext{A} \) is at \( x = 0.4 \ ext{m} \). At a point \( x \) between the wires, the field cancels when \[ B_a = B_b \].
03

Formulate the Equation for Cancellation Between Wires in the Same Direction

Using the formula \[ B = \frac{\mu_0 I}{2\pi r} \], the fields are \[ \frac{\mu_0 I_a}{2\pi x} = \frac{\mu_0 I_b}{2\pi (0.4-x)} \]. This simplifies to \[ \frac{I_a}{x} = \frac{I_b}{0.4-x} \]. Substitute \( I_a = 25.0 \) A and \( I_b = 75.0 \) A.
04

Solve the Equation for \\(x\\)

From \[ \frac{25}{x} = \frac{75}{0.4-x} \], cross-multiply to get \[ 25(0.4-x) = 75x \], which simplifies to \[ 25 \cdot 0.4 - 25x = 75x \]. Solving for \( x \): \[ 10 = 100x \Rightarrow x = 0.1 \ ext{m} \].
05

Setup for Currents in Opposite Directions

When the currents are in opposite directions, the magnetic fields reinforce each other on the outside points. Outside the wires, the fields cancel when their magnitudes are equal and point in the same direction. We solve \[ \frac{I_a}{x} = \frac{I_b}{x-0.4} \] for \(x > 0.4 \).
06

Solve for Cancellation Point Outside Wires (Opposite Currents)

Cross-multiply the equation \[ \frac{25}{x} = \frac{75}{x-0.4} \] to get \[ 25(x - 0.4) = 75x \], which leads to \[ 25x - 10 = 75x \]. Solving for \( x \): \[ 65x = 10 \Rightarrow x = 0.1538 \ ext{m} \], which is not valid since points must be outside wires. Instead, solving \[ \frac{25}{0.4-x} = \frac{75}{x+0.4} \] gives \( x = 1.2 \ ext{m} \).
07

Conclusion of Possible Points

For currents in the same direction:- The magnetic field is zero at \( x = 0.1 \ ext{m} \) between the wires.For currents in opposite directions:- Outside the wire, the field is zero at \( x = 0.133 \ ext{m} \) (beyond one of the wires).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Current-Carrying Wire
A current-carrying wire generates a magnetic field around it. This concept is key in understanding many electromagnetic phenomena. When a wire carries an electric current, it generates a magnetic field that circulates around it in concentric circles.
The strength of the magnetic field at a given distance from the wire depends on the magnitude of the current and the distance from the wire. The greater the current, the stronger the magnetic field. Conversely, as you move further from the wire, the strength of the magnetic field decreases. This relationship is crucial for analyzing situations where multiple wires interact. The direction of the magnetic field produced by a current-carrying wire can be determined using the right-hand rule. Simply point the thumb of your right hand in the direction of the current, and the curl of your fingers shows the direction of the magnetic field lines. This visualization helps when dealing with scenarios involving multiple wires and fields interacting.
Permeability of Free Space
The permeability of free space, denoted by \( \mu_0 \), is a constant that indicates how well a magnetic field can penetrate through the vacuum of space. It plays a vital role in calculating the magnetic field generated by a current-carrying wire. The value of \( \mu_0 \) is \( 4\pi \times 10^{-7} \ \, \mathrm{T} \! imes\, \mathrm{m/A} \), where T stands for Tesla, the unit of magnetic field, and A stands for Ampere, the unit of current.
This parameter is not just a constant to memorize; it provides insight into how magnetic fields work in space devoid of material substances. It essentially acts as a scaling factor in the formula for the magnetic field around a current-carrying wire, \( B = \frac{\mu_0 I}{2\pi r} \). Understanding \( \mu_0 \) helps in grasping how efficiently space transmits magnetic forces, and it is crucial for solving problems involving multiple magnetic fields and their interactions.
Cancellation of Magnetic Fields
Cancellation of magnetic fields happens when two magnetic fields interact in such a way that they nullify each other's effect at a particular point or region. This occurs when the magnetic fields generated by current-carrying wires have equal magnitude but opposite direction at certain points.
The conditions for cancellation depend on the directions and magnitudes of currents in nearby wires. When currents are in the same direction, the magnetic fields between them work against each other, potentially leading to a zero net magnetic field at certain points. However, when currents flow in opposite directions, their magnetic fields can cancel out externally, meaning outside the space between the wires. Engineers and scientists exploit such principles to minimize magnetic interference and achieve desired field conditions in various applications.
Direction of Currents
The direction of currents in wires significantly affects how their magnetic fields interact. This direction determines the orientation and interaction pattern of the fields according to the right-hand rule. When currents in parallel wires flow in the same direction, their magnetic fields between the wires oppose each other. This opposition can lead to cancellation at specific points, known as null points, where the net magnetic field equals zero.
Conversely, when the currents flow in opposite directions, their magnetic fields reinforce each other between the wires. In such cases, cancellation occurs outside the region bounded by the wires. Understanding how the currents' direction influences the behavior of magnetic fields is crucial not just for solving textbook problems but for designing electrical systems and understanding phenomena like electromagnetic interference.

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Most popular questions from this chapter

The current in the windings of a toroidal solenoid is 2.400 A. There are 500 turns, and the mean radius is 25.00 \(\mathrm{cm} .\) The toroidal solenoid is filled with a magnetic material. The magnetic field inside the windings is found to be 1.940 T. Calculate (a) the relative permeability and (b) the magnetic susceptibility of the material that fills the toroid.

A closely wound, circular coil with a diameter of 4.00 \(\mathrm{cm}\) has 600 turns and carries a current of 0.500 A. What is the magnitude of the magnetic field (a) at the center of the coil and (b) at a point on the axis of the coil 8.00 \(\mathrm{cm}\) from its center?

The Magnetic Field from a Lightning Bolt. Lightning bolts can carry currents up to approximately 20 kA. We can model such a current as the equivalent of a very long, straight wire. (a) If you were unfortunate enough to be 5.0 m away from such a lightning bolt, how large a magnetic field would you experience? (b) How does this field compare to one you would experience by being 5.0 \(\mathrm{cm}\) from a long, straight household current of 10 A ?

Two long, parallel wires are separated by a distance of 2.50 \(\mathrm{cm} .\) The force per unit length that each wire exerts on the other is \(4.00 \times 10^{-5} \mathrm{N} / \mathrm{m},\) and the wires repel each other. The current in one wire is 0.600 A. (a) What is the current in the second wire? (b) Are the two currents in the same direction or in opposite directions?

A long, straight wire lies along the \(y\) -axis and carries a current \(I=8.00 \mathrm{A}\) in the \(-y\) -direction (Fig. \(\mathrm{E} 28.23\) ). In addition to the magnetic field due to the current in the wire, a uniform magnetic field \(\vec{\boldsymbol{B}}_{0}\) with magnitude \(1.50 \times 10^{-6} \mathrm{T}\) is in the \(+x\) -direction What is the total field (magnitude and direction) at the following points in the \(x z\) -plane: (a) \(x=0, z=\) \(1.00 \mathrm{m} ;\) (b) \(x=1.00 \mathrm{m}, \quad z=0\) (c) \(x=0, z=-0.25 \mathrm{m} ?\)

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