Chapter 28: Problem 23
A long, straight wire lies along the \(y\) -axis and carries a current \(I=8.00 \mathrm{A}\) in the \(-y\) -direction (Fig. \(\mathrm{E} 28.23\) ). In addition to the magnetic field due to the current in the wire, a uniform magnetic field \(\vec{\boldsymbol{B}}_{0}\) with magnitude \(1.50 \times 10^{-6} \mathrm{T}\) is in the \(+x\) -direction What is the total field (magnitude and direction) at the following points in the \(x z\) -plane: (a) \(x=0, z=\) \(1.00 \mathrm{m} ;\) (b) \(x=1.00 \mathrm{m}, \quad z=0\) (c) \(x=0, z=-0.25 \mathrm{m} ?\)
Short Answer
Step by step solution
Understanding the Problem
Use Biot-Savart Law for Current-Carrying Wire
Find Magnetic Field at Point (a)
Find Magnetic Field at Point (b)
Find Magnetic Field at Point (c)
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Biot-Savart Law
- \(\mu_0\) is the permeability of free space, with a value of \(4\pi \times 10^{-7} \text{T}\cdot\text{m/A}\).
- \(dL\) is the current element.
- \(\hat{r}\) is the unit vector from the wire to the point where the field is being calculated.
Ampere's Law
- The integral \(\oint B \cdot dL\) is taken over the closed loop.
- \(I_{enc}\) is the current enclosed by the loop.