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Fields Within the Atom. In the Bohr model of the hydrogen atom, the electron moves in a circular orbit of radius \(5.3 \times 10^{-11} \mathrm{m}\) with a speed of \(2.2 \times 10^{6} \mathrm{m} / \mathrm{s} .\) If we are viewing the atom in such a way that the electron's orbit is in the plane of the paper with the electron moving clockwise, find the magnitude and direction of the electric and magnetic fields that the electron produces at the location of the nucleus (treated as a point).

Short Answer

Expert verified
Electric field: inward, magnitude \(5.14 \times 10^{11} \text{ N/C}\). Magnetic field: out of the paper, magnitude \(1.26 \times 10^{-5} \text{ T}\).

Step by step solution

01

Identify Known Values

Identify the given values in the problem. We have the radius of the orbit, \( r = 5.3 \times 10^{-11} \text{ m} \) and the speed of the electron, \( v = 2.2 \times 10^{6} \text{ m/s} \).
02

Calculate Electric Field Produced by the Electron

To calculate the electric field \( E \) produced by the electron at the nucleus, use Coulomb's law for a point charge, \( E = \frac{k \cdot e}{r^2} \), where \( e = 1.6 \times 10^{-19} \text{ C} \) is the charge of the electron, \( k = 8.99 \times 10^9 \text{ N m}^2/\text{C}^2 \) is Coulomb's constant, and \( r \) is the radius of the orbit. Substitute the known values to find \( E \).
03

Calculate the Magnetic Field Produced by the Electron

The magnetic field \( B \) produced by a moving charge is given by \( B = \frac{\mu_0 \cdot e \cdot v}{2 \pi r^2} \), where \( \mu_0 = 4\pi \times 10^{-7} \text{ T m/A} \) is the permeability of free space. Substitute the known values into the formula to find \( B \).
04

Determine the Direction of the Fields

The direction of the electric field produced by the electron at the nucleus is radially inward, because the electron has a negative charge. The direction of the magnetic field can be found using the right-hand rule: point your thumb in the direction of the velocity (clockwise in the plane), and the fingers curl in the direction of the magnetic field at the center, which is out of the paper.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Electric Field
An electric field is a region around a charged particle where an electric force is exerted on other charges. In the Bohr model of the hydrogen atom, the electron produces an electric field at the nucleus.
To calculate the electric field (E) at the location of the nucleus, we use Coulomb's law for a point charge. This law states that the electric field due to a point charge is given by the formula:
\[ E = \frac{k \cdot e}{r^2} \]
- E is the magnitude of the electric field- E is the charge of the electron (1.6 \times 10^{-19} \, C)- r is the distance from the electron to the nucleus, which is the radius of the orbit (5.3 \times 10^{-11} \, m)
This electric field points radially inward towards the center because electrons have a negative charge and attract opposite charges, such as the positively charged nucleus.
So:
- An electric field exerts a force on other charges within the field- The field's direction is determined by the nature of the charge producing it
Understanding the electric field is essential when studying charged particles like electrons within an atom.
Magnetic Field
When a charged particle, such as an electron, moves it creates a magnetic field. In the Bohr model, the orbiting electron generates a magnetic field at the nucleus' location. This is due to the circulating current resulting from the electron's motion.
The magnetic field (B) produced by the moving electron can be calculated using the formula:
\[ B = \frac{\mu_0 \cdot e \cdot v}{2 \pi r^2} \]
- \mu_0 is the permeability of free space (4\pi \times 10^{-7} \, T \, m/A)- e is the electron's charge (1.6 \times 10^{-19} \, C)- v is the velocity of the electron (2.2 \times 10^6 \, m/s)- r is the radius of the orbit
The magnetic field's direction is determined by the right-hand rule. If you point your thumb in the direction of electron movement (clockwise in this case), your fingers curl in the direction of the magnetic field; hence, it's out of the paper.
The magnetic field is a crucial concept as it helps understand the complex interactions between moving charges and their environments.
Coulomb's Law
Coulomb's law is a fundamental principle for understanding the electric interactions between charged particles. It provides a way to calculate the force between two point charges.
The significance of Coulomb's law lies in its contribution to concepts like the electric field in the Bohr model of hydrogen:
- The law is expressed mathematically as:\[ F = \frac{k \cdot Q_1 \cdot Q_2}{r^2} \]- F is the force between two charges- \(\mathbf{k}\) is Coulomb's constant (8.99 \times 10^9 \, N m^2 / C^2)- \(\mathbf{Q_1} \ \text{and} \ Q_2\) are the charges- \(\mathbf{r}\) is the distance between the centers of the two charges
In the context of the Bohr model, Coulomb's law helps us determine the magnitude of the electric field produced by the electron. Understanding this principle is vital, as it explains why charged particles interact and gives insight into the forces that maintain atomic and molecular structures.
Permeability of Free Space
The permeability of free space is a constant that appears in fundamental equations related to magnetism. It is denoted by \( \mathbf{\mu_0} \)and plays a crucial role in calculating magnetic fields, such as those produced by moving charges.
In the Bohr model of the hydrogen atom:
  • The permeability of free space is defined as \(4\pi \times 10^{-7} \, T m/A\)
  • This constant helps determine the magnetic field strength generated by the moving electron
When calculating the magnetic field (B), the permeability of free space is a key factor:
- \( B = \frac{\mu_0 \cdot e \cdot v}{2 \pi r^2} \)- The \( \mu_0 \) value signifies how much the magnetic field can "penetrate" a vacuum
This concept is foundational for understanding how magnetic fields behave in various environments, contributing to our comprehension of atomic structures and the forces at play on a microscopic level.

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Most popular questions from this chapter

A wooden ring whose mean diameter is 14.0 \(\mathrm{cm}\) is wound with a closely spaced toroidal winding of 600 turns. Compute the magnitude of the magnetic field at the center of the cross section of the windings when the current in the windings is 0.650 \(\mathrm{A}\) .

Two long, straight conducting wires with linear mass density \(\lambda\) are suspended from cords so that they are each horizontal, parallel to each other, and a distance \(d\) apart. The back ends of the wires are connected to each other by a slack, low-resistance connecting wire. A charged capacitor (capacitance \(C )\) is now added to the system; the positive plate of the capacitor (initial charge \(+Q_{0}\) ) is connected to the front end of one of the wires, and the negative plate of the capacitor (initial charge \(-Q_{0} )\) is connected to the front end of the other wire (Fig. P28.87). Both of these connections are also made by slack, low-resistance wires. When the connection is made, the wires are pushed aside by the repulsive force between the wires, and each wire has an initial horizontal velocity of magnitude \(v_{0} .\) Assume that the time constant for the capacitor to discharge is negligible compared to the time it takes for any appreciable displacement in the position of the wires to occur. (a) Show that the initial speed \(v_{0}\) of either wire is given by $$ v_{0}=\frac{\mu_{0} Q_{0}^{2}}{4 \pi \lambda R C d} $$ where \(R\) is the total resistance of the circuit. (b) To what height \(h\) will each wire rise as a result of the circuit connection?

A short current element \(d \vec{l}=(0.500 \mathrm{mm}) \hat{\jmath}\) carries a current of 8.20 \(\mathrm{A}\) in the same direction as \(d \vec{l} .\) Point \(P\) is located at \(\vec{r}=(-0.730 \mathrm{m}) \hat{\imath}+(0.390 \mathrm{m}) \hat{k} .\) Use unit vectors to express the magnetic field at \(P\) produced by this current element.

BIO Currents in the Brain. The magnetic field around the head has been measured to be approximately \(3.0 \times 10^{-8}\) G. Although the currents that cause this field are quite complicated, we can get a rough estimate of their size by modeling them as a single circular current loop 16 \(\mathrm{cm}\) (the width of a typical head) in diameter. What is the current needed to produce such a field at the center of the loop?

Two concentric circular loops of wire lie on a tabletop, one inside the other. The inner wire has a diameter of 20.0 \(\mathrm{cm}\) and carries a clockwise current of \(12.0 \mathrm{A},\) as viewed from above, and the outer wire has a diameter of 30.0 \(\mathrm{cm} .\) What must be the magnitude and direction (as viewed from above) of the current in the outer wire so that the net magnetic field due to this combination of wires is zero at the common center of the wires?

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